Answer:
0.027
Step-by-step explanation:
The p-value for Jane's chi-square test for goodness of fit is computed by using value of test statistic and degree of freedom.
Using Excel function CHISQ.DIST.RT(7.24,2) for computing p-value for chi-square goodness of fit test. 7.24 is the value of test statistic and 2 is degree of freedom. The resultant value is 0.026783. By rounding off to three decimal places the required p-value is 0.027.
-3-6=-9 yards losing 3 and losing 6 on two plays would be losing 9 plays in total -9
Answer:
3rd one
Step-by-step explanation:
because it's close
Division. The answer is 5 1/6.
