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kupik [55]
2 years ago
8

A hotel plans to use marble for part of the floor lobby. The marble section of the floor will be in the shape of a triangle with

a base of 80 feet and a height of 60 feet. The marble flooring costs $6 per square foot. How much will the marble for the floor cost?
Mathematics
2 answers:
lidiya [134]2 years ago
8 0
It will cost $14,400 to do the triangle the hotel plans to do.
cricket20 [7]2 years ago
8 0
The area of a triangle is half the base times the height:

A=\dfrac{b\cdot h}{2}

Thus, the area of the marble section is:

A=\dfrac{80 \cdot 60}{2} = 2,400 \text{ square feet}

If every square foot costs $6, the total cost is:

2,400 · 6 = $14,400
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What is the area of a regular polygon with 100 sides and a perimeter of 100 units?
PolarNik [594]
Now, if the regular polygon has 100 sides, and the perimeter is 100 units, that simply means that each side is 1 unit, foot, meter, else.

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\bf \textit{area of a regular polygon}\\\\
A=\cfrac{1}{4}ns^2cot\left( \frac{180}{n} \right)\quad 
\begin{cases}
n=\textit{number of sides}\\
s=\textit{length of a side}\\
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3 years ago
abcd is an isosceles trapezoid with legs ab and cd and base bc if the length of ab =-3y+54 the leingth of bc =5y+2 and the leing
Vilka [71]

ANSWER

y = 5

EXPLANATION

The given isosceles tra-pezoid has legs

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Step-by-step explanation:

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erastovalidia [21]

Answer:

2/8(x) - 4 = 2

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