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kupik [55]
3 years ago
8

A hotel plans to use marble for part of the floor lobby. The marble section of the floor will be in the shape of a triangle with

a base of 80 feet and a height of 60 feet. The marble flooring costs $6 per square foot. How much will the marble for the floor cost?
Mathematics
2 answers:
lidiya [134]3 years ago
8 0
It will cost $14,400 to do the triangle the hotel plans to do.
cricket20 [7]3 years ago
8 0
The area of a triangle is half the base times the height:

A=\dfrac{b\cdot h}{2}

Thus, the area of the marble section is:

A=\dfrac{80 \cdot 60}{2} = 2,400 \text{ square feet}

If every square foot costs $6, the total cost is:

2,400 · 6 = $14,400
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Step-by-step explanation:

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PLS help ASAP I DONT have time to answer this, it also detects if it’s right or wrong.
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4 0
3 years ago
Please identify the common angles and sides or if there are non. Explain all work please!
vova2212 [387]

Answers:

Common angles: ΔBGC and ΔGDC

Common sides: ΔGE and ΔAG

A common angle is a triangle that exists in two or both of the triangles.

Here, the common angles should be ΔBGC and ΔGDC.

These two angles are triangles, and they consist in both triangles.

A common side is when two angles have one vertex in the same area.

Here, we see that the common sides are ΔGE, because they intersect.

Another common side we see here is ΔAG, because they also intersect.

Hope this answer helps you!

8 0
3 years ago
Twoooooooooooooooooooooooooooo
KatRina [158]

Answer:

n = 60.22

Step-by-step explanation:

Hello

To find Sn, we need to draw out equations for each a₇ and a₁₉

In an arithmetic progression,

Sn = a + (n-1)d

Where Sn = sum of the A.P

a = first term

d = common difference

a₇ = 32

32 = a + (7-1)d

32 = a + 6d ........equation (i)

a₁₉ = 140

140 = a + (19-1)d

140 = a + 18d .........equation (ii)

Solve equation (i) and (ii) simultaneously

From equation (i)

32 = a + 6d

Make a the subject of formula

a = 32 - 6d .....equation (iii)

Put equation (iii) into equation (ii)

140 = (32 - 6d) + 18d

140 = 32 - 6d + 18d

Collect like terms

140 - 32 = 12d

12d = 108

d = 108 / 12

d = 9

Put d = 9 in equation (i)

32 = a + 6(9)

32 = a + 54

a = 32 - 54

a = -22

When Sn = 511

Sn = a + (n - 1)d

Substitute and solve for n

511 = -22 + (n-1) × 9

511 = -22 + 9n - 9

511 = -31 + 9n

511 + 31 = 9n

542 = 9n

n = 542 / 9

n = 60.22

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3 years ago
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antiseptic1488 [7]
6.93 
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5 0
3 years ago
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