Answer:
The expression used to find the change in temperature per hour is Algebraic expression
Thus per hour; the temperature falls at the rate of
Step-by-step explanation:
A temperature falls from 0 to
in 
Which expression finds the change in temperature per hour.
From the above given information;
The initial temperature is 0
The final temperature is
The change in temperature is 


Thus;
-12.25 ° = 3.5 hours
To find the change in x° per hour; we have;
x° = 1 hour
The expression used to find the change in temperature per hour is Algebraic expression
From above if we cross multiply ; we have;
(- 12.25° × 1 hour) = (x° × 3.5 hour)
Divide both sides by 3.5 hours; we have:

x° = - 3.5
x° = 
Thus per hour; the temperature falls at the rate of
View the attached photo.
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The quadratic function, y = x2, has an x-intercept at the origin = TRUE</span>
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The quadratic function, y = x2 + 3, has an x-intercept at the origin = FALSE</span>
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From x = -2 to x = 0, the average rate of change for both functions is positive = FALSEWhen viewing a graph, you start from the left and go to right and from left to right from -2 to 0 the graph is declining.
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From x = -2 to x = 0, the average rate of change for both functions is negative = TRUEBoth are declining if you read the graph from left to right.
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For the quadratic function, y = x2, the coordinate (2, 3) is a solution to the equation of the function. = FALSE</span><span>
y = x^2
If we insert 2 into y = x^2 we get y = 4 but our point (2,3) has y = 3
</span>
For the quadratic function, y = x2 + 3, the coordinate (2, 7) is a solution to the equation of the function. = TRUE
If we insert 2 for x, we see that y = x^2 + 3 = y = 2^2 + 3 = y = 7 and our y value in the point (2,7) is 7.
Answer:
It is 2/4 equal to 1/2 (2.5)