Represent these consecutive numbers (assuming that they are all integers):
x
x+1
x+2
x+3
x+4
x+5
and so on
x+8
x+9 is the tenth number. x+9 = 10, so x = 9.
Think of it this way: there are 10 consecutive numbers, and the last one is 10.
Working backwards, we get the sequence 10, 9, ... 3, 2, 1.
The sum of such an arith sequence is equal to the count of the numbers times the average of the first and last terms:
sum here = 10(1+10)/2 = 5(11) = 55 (answer)
Answer:
heres an example of substitution in a world problem. hope this helps on some other problens
Answer: I know R2 is reflexive property.
Step-by-step explanation:
Answer:
$22.5
Step-by-step explanation:
25% of $90
25% x 90
0.25 x 90
$22.5
Answer: Nothing multiplies to 40 and adds to -6, it is impossible
