All categories

3 years ago

Which equation is equivalent to the equation below? 35a+ 20

Mathematics

1 answer:

Arturiano [62]3 years ago

4 0

5(7a + 4b)
Distributive property !

You might be interested in

How many different integers can have the same absolute value? Give a example.

nikdorinn [45]

Up to 2 integers can have the same absolute value (a number and its opposite).

For example, 2 and -2 have the same absolute value. 5 and -5 also have the same absolute value.

6 0

3 years ago

Read 2 more answers

Write the equation of the line in slope intercept form that goes through points (1,8) and (5,20)

pantera1 [17]

Answer:

y=3x+5

Step-by-step explanation:

Point slope equation:

y=mx+b

m-slope, b- is y-intercept

equation given 2 points

y-y1 = m(x-x1)

For point (1,8) and slope m=(y2-y1)/(x2-x1) = 20-8/5-1=12/4=3

y-8 =3(x-1)

arange it in point slope format

y-8=3x-3

y=3x-3+8

y=3x+5

6 0

4 years ago

Reflecting<br><br> Gcse foundation

mote1985 [20]

Answer:

I think this is the correct answer.

6 0

3 years ago

plz help I will give the brainlist David drew this diagram of a picture frame he is going to make. Each square represents 1 squa

IRISSAK [1]

Answer:

Step-by-step explanation:

7 0

3 years ago

Serhud [2]

A circle is characterized by radius, arc, sectors and circumference

The length of the major arc is $18.75\pi$
The radius of the circle is 15
The area of the shaded sector is $140.625 * \pi$

<h3>Length of the major arc</h3>

The given parameters are:

$C = 30\pi$ --- the circumference

$\theta = 225^o$ -- the center angle

The length of the major arc is calculated using:

$L = \frac{\theta}{360} * C$

So, we have:

$L = \frac{225}{360} *30\pi$

Evaluate

$L = 18.75\pi$

Hence, the length of the major arc is $18.75\pi$

<h3>The radius of the circle</h3>

The circumference is given as:

$C = 30\pi$

So, we have:

$2\pi r = 30\pi$

Divide through by 2pi

$r = 15$

Hence, the radius of the circle is 15

<h3>The area of the shaded sector</h3>

The area of a sector is:

$A = \frac{\theta}{360} * \pi r^2$

So, we have:

$A = \frac{225}{360} * \pi * 15^2$

Evaluate

$A = 140.625 * \pi$

Hence, the area of the shaded sector is $140.625 * \pi$