All categories

3 years ago

What is 372 rounded to the nearest 100

2 answers:

7 0

372

The number 3 is in the hundreds place.

Look to the number immediately to the right.

We know that 7 is bigger than 3.

So, we add 1 to 3 and the rest become 0.

Answer: 400

NeX [460]3 years ago

4 0

372 rounded to the nearest hundred would be 400.
The answer is 400 because 372 is closer to 400 than 300.

Hope this helped :).

You might be interested in

A volleyball reaches its maximum of 13 feet, 3 seconds after it is served. What quadratic formula could model the height of the

Katena32 [7]

Answer:

$H=-(t-3)^2+13$

Step-by-step explanation:

The path covered by the volleyball will be a downward parabola with the vertex being the highest point of the ball.

A general form of a downward parabola is given as:

$y=-a(x-h)^2+k$

Where $(h,k)$ is the vertex of the parabola and 'a' is a constant.

Now, let 'h' be the vertical height and 't' be the time taken.

So, the equation would be of the form:

$H=-a(t-h)^2+k$

Now, as per question:

h = 2 seconds, k = 13 feet.

$H=-a(t-3)^2+13$

Now, taking a = 1. So, the formula that can be used is:

$H=-(t-3)^2+13$

7 0

3 years ago

Write a system of inequalities using the given graph

ziro4ka [17]

For dark line

(0,1)
(-1,-4)

Slope

m=-4-1/-1=5

Equation in point slope form

y-1=5x
y=5x+1

Put (0,0)

As line is dark sign is ≤

The inequality

y≤5x+1

For dashed line

(2,0)
(0,-2)

Equation in intercept form

x/2-y/2=1
x-y=2
y=x-2

Put (0,0)

0>-2

Symbol is >

Inequality is

y>x-2

7 0

2 years ago

Y=x^2-6x-16 in vertex form

satela [25.4K]

Answer:

$y=(x-3)^{2} -25$

Step-by-step explanation:

The standard form of a quadratic equation is $y=ax^{2} +bx+c$

The vertex form of a quadratic equation is $y=a(x-h)^{2} +k$

The vertex of a quadratic is (h,k) which is the maximum or minimum of a quadratic equation. To find the vertex of a quadratic, you can either graph the function and find the vertex, or you can find it algebraically.

To find the h-value of the vertex, you use the following equation:

$h=\frac{-b}{2a}$

In this case, our quadratic equation is $y=x^{2} -6x-16$ . Our a-value is 1, our b-value is -6, and our c-value is -16. We will only be using the a and b values. To find the h-value, we will plug in these values into the equation shown below.

$h=\frac{-b}{2a}$ ⇒ $h=\frac{-(-6)}{2(1)}=\frac{6}{2} =3$

Now, that we found our h-value, we need to find our k-value. To find the k-value, you plug in the h-value we found into the given quadratic equation which in this case is $y=x^{2} -6x-16$

$y=x^{2} -6x-16$ ⇒ $y=(3)^{2} -6(3)-16$ ⇒ $y=9-18-16$ ⇒ $y=-25$