Jordana wrote the equation for a linear relationship as y = -8x-4. For what value of x is y equal to -16

1 answer:

3 0

So our two equations are y=-8x-4 and y=-16, and since in both equations, something equals the same y, those two are the same. So we can combine the two into -16=-8x-4. In the question, they are asking to solve for x. So to do that, you need to isolate your variable. Now for solving algebraic equations, you use reverse PEMDAS (SADMEP), meaning you add 4 to both sides to clear the -4 one the rights side to get -12=-8x. Then you divide both sides by -8 to get 12/8, which simplifies to 3/2.

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Solve for x (1/x) -2/3 = (4x)

Vadim26 [7]

The value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

Step-by-step explanation:

The equation is $\frac{1}{x}-\frac{2}{3}=4 x$

Subtracting by $4x$ on both sides,

$\frac{1}{x}-\frac{2}{3}-4 x=0$

Taking LCM,

$\frac{3-12 x^{2}-2 x}{3 x}=0$

Multiplying by 3x on both sides,

$-12 x^{2}-2 x+3=0$

Dividing by (-) on both sides,

$12 x^{2}+2 x-3=0$

Using quadratic formula, we can solve for x.

$\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}$