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photoshop1234 [79]
3 years ago
7

Chau and Yoko each opened a savings account today. Chau opened his account with a starting amount of $460, and he is going to pu

t in $60 per month. Yoko opened her account with a starting amount of $530, and she is going to put in $50 per month.
Let x be the number of months after today.

(a) For each account, write an expression for the amount of money in the account after x months.

Amount of money in Chau's account (In dollars) =

Amount of money in Yoko's account (in dollars) =

(b) Write an equation to show when the two accounts would have the same amount of money.
Mathematics
1 answer:
Ber [7]3 years ago
7 0

Answer:

A1-60x+460

A2-50x+530

B-60x7+460

50x7+530

Step-by-step explanation:

A1 and A2-since x is equivalent to number of months we multiply the number of months then add it to the original cost to get how much total you get in the account.

B-you add 50 to 530 and 60 to 460 until they equal the same amount in this case its 7 times.

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Time = 8 years
Sedaia [141]
B)1,131.20 would be the answer. 1010x0.14=141.4x8=B                                                                        
 
7 0
3 years ago
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A total of 579 tickets were sold for the school play they were either adult tickets or student tickets. there were 71 fewer stud
stepan [7]

Answer: 325

Step-by-step explanation:

Student tickets: x

Adult tickets: x + 71

Total: 579

x + x + 71 = 579

2x + 71 = 579

2x = 579 - 71

2x = 508

x = 508/2

x = 254

Adult tickets = x + 71 = 254 + 71 = 325

P.S. Hope it helps. If you have any questions, feel free to ask them here. I'll be happy to help! Have a wonderful day!

4 0
2 years ago
Evaluate the given integral by changing to polar coordinates. sin(x2 y2) dA R , where R is the region in the first quadrant betw
alexira [117]

Answer:

I = 1.47001

Step-by-step explanation:

we have the function

f(x,y)=sin(x^2y^2)\\

In polar coordinates we have

x=rcos\theta\\y=rsin\theta

and dA is given by

dA=rdrd\theta

Hence, the integral that we have to solve is

I=\int \limt_2^4 \int \limit_0^{\pi /2}sin(r^4cos^2\theta sin^2\theta)rdrd\theta

This integral can be solved in a convenient program of your choice (it is very difficult to solve in an analytical way, I use Wolfram Alpha on line)

I = 1.47001

Hope this helps!!!

7 0
3 years ago
X+6y=27<br> 7x-3y=9 por metodo de igualacion
GalinKa [24]

Answer:

(3,4)

Step-by-step explanation:

The system of equations is:

x+6y=27

7x-3y=9.

I looked up "metodo de igualacion". It is basically American for doing substitution.

However, the only difference is you are asked to solve both equations for a variable.

The first equation looks easy to solve for x. So I'm going to solve both equations for x.

x+6y=27

Subtract 6y on both sides:

x     =-6y+27

7x-3y=9

Add 3y on both sides:

7x    =3y+9

Divide both sides by 7:

x     =3/7 y +9/7

So both equations are solved for x.  You want to find when the x's are the same because you are looking for a common amongst the lines given.

So we have

-6y+27=3/7 y  +9/7

I hate the fractions honestly so I'm going to multiply both sides by 7 so they will no longer be for now:

-42y+189=3y + 9

Now add 42y on both sides:

         189=45y+9

Subtract 9 on both sides:

        180=45y

Divide both sides by 45:

            4=y

If 4=y, then y=4.

So now once we have obtain 4 for y, we will use one of the equations given along with it to find x. Just choose one. Choose the easier looking one to you.

I like the x=-6y+27 with y=4.

So replace y with giving you:

x=-6(4)+27

x=-24+27

x=3

So the solution is (x,y)=(3,4).

x=3 and y=4.

8 0
3 years ago
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Alika [10]
The congruence theorem that you can use is AAS because you can see from the image that 2 angles and 1 side are equal. AAS(angle angle side)
8 0
4 years ago
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