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3 years ago

How to I solve this geometry I don’t know

Mathematics

1 answer:

nikdorinn [45]3 years ago

3 0

Look carefully at the diagram. The shaded region represents 3/4 of the total area of the circle, which, in turn, is pi*r^2, or pi*(8 cm)^2.

Thus, the area of the shaded region is (3/4)*pi*(64 cm^2), or 48 pi cm^2.

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If 8 is subtracted from 7 times a number the result is 34

djverab [1.8K]

7x - 8 = 34

Solving:

7x = 34 + 8
7x = 42
x = 6

Hope this helps!

5 0

4 years ago

A college requires applicants to have an ACT score in the top 12% of all test scores. The ACT scores are normally distributed, w

DochEvi [55]

Answer:

a) The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b) 156 would be expected to have a test score that would meet the colleges requirement

c) The lowest score that would meet the colleges requirement would be decreased to 26.388.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 21.5, \sigma = 4.7$

a. Find the lowest test score that a student could get and still meet the colleges requirement.

This is the value of X when Z has a pvalue of 1 - 0.12 = 0.88. So it is X when Z = 1.175.

$Z = \frac{X - \mu}{\sigma}$

$1.175 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.175*4.7$

$X = 27.0225$

The lowest test score that a student could get and still meet the colleges requirement is 27.0225.

b. If 1300 students are randomly selected, how many would be expected to have a test score that would meet the colleges requirement?

Top 12%, so 12% of them.

0.12*1300 = 156

156 would be expected to have a test score that would meet the colleges requirement

c. How does the answer to part (a) change if the college decided to accept the top 15% of all test scores?

It would decrease to the value of X when Z has a pvalue of 1-0.15 = 0.85. So X when Z = 1.04.

$Z = \frac{X - \mu}{\sigma}$

$1.04 = \frac{X - 21.5}{4.7}$

$X - 21.5 = 1.04*4.7$

$X = 26.388$

The lowest score that would meet the colleges requirement would be decreased to 26.388.

6 0

4 years ago

Si -x+y+z=75, entonces -(x+3)+(y-5)+(z-6)=

jenyasd209 [6]

Answer:

Step-by-step explanation:

● -(x + 3) + (y - 5) + (z - 6)

● -x - 3 + y - 5 + z - 6

● (-x + y + z) + (3 -5 -6)

● 75 + 3 - 11

● 78 - 11

● 67

8 0

3 years ago

What is an imaginary number?

trapecia [35]

An imaginary number is a complex number that can be written as a real number multiplied by the imaginary unit i, which is defined by it's property i² = −1. The square of an imaginary number bi is −b². For example, 5i is an imaginary number, and it's square is −25.

8 0

3 years ago

Stardom form 5 tens+5 tens

fiasKO [112]

100 in standard form.

8 0

3 years ago