Five applicants are to be scheduled for job interviews at five given times. On an application form, each applicant was asked to
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ΔABC is a 45 - 45 - 90 triangle. The pattern of its sides is as follows:
Each leg = 1 unit (and both legs are that way, since the triangle is isosceles - so two sides are the same)
Hypotenuse = √2 units.
So if we know either leg, we multiply by √2 to get the hypotenuse. In reverse, we divide by √2 if we know the hypotenuse to get the measurement of a leg.
Our problem tells us that the hypotenuse AC is 10 units. We divide 10 by √2 to get the measurement of leg AB. Since it's a 45 -45 - 90 triangle, AB = BC.
to rationalize the radical
Thus, each leg is 5\sqrt{2} [/tex].
Answer:
Arc length XPY =28.26 m.
Step-by-step explanation:
Given : A circle with two arc XY and XPY and radius 6 m.
To find : Arc length XPY.
Solution : We have given that arc XY and XPY .
Radius = 6 m.
Central angle formed by arc XPY = 360 - 90 = 270.
Arc length = 2 *pi* r ( .
Plugging the values
Arc length = 2 *3.14 * 6 ( .
Arc length =37.68 ( .
Arc length =37.68 * 0.75
Arc length XPY =28.26 m.
Therefore, Arc length XPY =28.26 m.
Answer:
Step-by-step explanation:
Using trigonometric ratio cos.
Here,
- Theta = θ = x
- Adjacent = 12
- Hypotenuse = 28