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never [62]
3 years ago
8

Five applicants are to be scheduled for job interviews at five given times. On an application form, each applicant was asked to

mark two out of the five times. What is the probability that each of them can be interviewed at one of the two times they have marked
Mathematics
1 answer:
dlinn [17]3 years ago
6 0

Answer:

0.01024

Step-by-step explanation:

Assume marking was done at random : Hence, each of the 5 time slots have equal Chamves of being marked ;

Number of time slots, n = 5

Required to mark, number of preferred timeslot x = 2

P(x) = 2 /5 = 0.4

Probability of 0.4 that an interviewee gets one of his preferred timeslot.

Probability that each of the 5 interviewees gets one of their preferred time slots :

Using the multiplication rule of independence :

0.4 * 0.4 * 0.4 * 0.4 * 0.4 = 0.4^5 = 0.01024

0.01024 * 100% = 1.024%

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You work at a pioneer historical site. On this site you have handcarts. One cart has a handle that connects to the center of the
Gelneren [198K]

Answer:

a)  see below

b)  radius = 16.4 in (1 d.p.)

c)  18°. Yes contents will remain. No, handle will not rest on the ground.

d)  Yes contents would spill.  Max height of handle = 32.8 in (1 d.p.)

Step-by-step explanation:

<u>Part a</u>

A chord is a <u>line segment</u> with endpoints on the <u>circumference</u> of the circle.  

The diameter is a <u>chord</u> that passes through the center of a circle.

Therefore, the spokes passing through the center of the wheel are congruent chords.

The spokes on the wheel represent the radii of the circle.  Spokes on a wheel are usually evenly spaced, therefore the congruent central angles are the angles formed when two spokes meet at the center of the wheel.

<u>Part b</u>

The <u>tangent</u> of a circle is always <u>perpendicular</u> to the <u>radius</u>.

The tangent to the wheel touches the wheel at point B on the diagram.  The radius is at a right angle to this tangent.  Therefore, we can model this as a right triangle and use the <u>tan trigonometric ratio</u> to calculate the radius of the wheel (see attached diagram 1).

\sf \tan(\theta)=\dfrac{O}{A}

where:

  • \theta is the angle
  • O is the side opposite the angle
  • A is the side adjacent the angle

Given:

  • \theta = 20°
  • O = radius (r)
  • A = 45 in

Substituting the given values into the tan trig ratio:

\implies \sf \tan(20^{\circ})=\dfrac{r}{45}

\implies \sf r=45\tan(20^{\circ})

\implies \sf r=16.37866054...

Therefore, the radius is 16.4 in (1 d.p.).

<u>Part c</u>

The measure of an angle formed by a secant and a tangent from a point outside the circle is <u>half the difference</u> of the measures of the <u>intercepted arcs</u>.

If the measure of the arc AB was changed to 72°, then the other intercepted arc would be 180° - 72° = 108° (since AC is the diameter).

\implies \sf new\: angle=\dfrac{108^{\circ}-72^{\circ}}{2}=18^{\circ}

As the handle of the cart needs to be no more than 20° with the ground for the contents not to spill out, the contents will remain in the handcart at an angle of 18°.

The handle will not rest of the ground (see attached diagram 2).

<u>Part d</u>

This can be modeled as a right triangle (see diagram 3), with:

  • height = (48 - r) in
  • hypotenuse ≈ 48 in

Use the sin trig ratio to find the angle the handle makes with the horizontal:

\implies \sf \sin (\theta)=\dfrac{O}{H}

\implies \sf \sin (\theta)=\dfrac{48-r}{48}

\implies \sf \sin (\theta)=\dfrac{48-45\tan(20^{\circ})}{48}

\implies \theta = 41.2^{\circ}\:\sf(1\:d.p.)

As 41.2° > 20° the contents will spill out the back.

To find the <u>maximum height</u> of the handle from the ground before the contents start spilling out, find the <u>height from center of the wheel</u> (setting the angle to its maximum of 20°):

\implies \sin(20^{\circ})=\dfrac{h}{48}

\implies h=48\sin(20^{\circ})

Then add it to the radius:

\implies \sf max\:height=48\sin(20^{\circ})+45\tan(20^{\circ})=32.8\:in\:(1\:d.p.)

(see diagram 4)

------------------------------------------------------------------------------------------

<u>Circle Theorem vocabulary</u>

<u>Secant</u>: a straight line that intersects a circle at two points.

<u>Arc</u>: the curve between two points on the circumference of a circle

<u>Intercepted arc</u>: the curve between the two points where two chords or line segments (that meet at one point on the other side of the circle) intercept the circumference of a circle.

<u>Tangent</u>: a straight line that touches a circle at only one point.

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2 years ago
Find mMK................
Gnesinka [82]

Answer:

Approximately mMK is 53 degrees

Step-by-step explanation:

Here, we want to find the length of MK

As we can see, we have a right triangle at LNK

so

let us find the angle at L first

9 is adjacent to the angle at L and also, 15 is the hypotenuse of the angle at L

so the trigonometric identity that connects adjacent to the hypotenuse is the cosine

It is the ratio of the adjacent to the hypotenuse

So;

cos L = 9/15

L = arc cos (9/15)

L = 53.13 degree

Approximately, L = 53 degrees

so now, we want to get the arc length MK

We are to use the angle-arc relationship here

Using this; arc length MK is equal to the measure of L at the center which is 53 degrees

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A smartphone costs ​$280. Sales tax is 8​%. What is the total​ cost, including​ tax
oee [108]

Answer:

it should cost 302.40$ all together

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Convert 40 ounces into pounds. Round your answer to the nearest tenth.
alex41 [277]

Answer:

Step-by-step explanation:

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