The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:
(X-h)^2 + (y-k)^2 = r^2
As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9
Substituting these values into the standard form of the equation of a circle given above:
(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81
The standard form is x^2 + y^2 =81
I’m pretty sure this is right
Answer:
199 if it's 7b^3 + 10
9271 if it's (7b)^3 + 10
Step-by-step explanation:
You just substitute the 3 in for d. If your expression was 7b^3 + 10, then only b is being raised to 3.
So 3^3 is 27, 27*7 is 189, 189+10 is 199.
If the expression was (7b)^3 + 10, then first you multiply 7 and 3 to get 21. Then you raise 21 to the power of 3, which is 9261. Then you add 10, which is 9271.
Answer:
D. Section A; students in this section scored between 1 and 10
Step-by-step explanation:
This answer is correct because the graph shows everything that was explained in the answer. Hope that helps!!
