Answer:
I cannot see the question clearly. But I know how to do .
Answer:
y = 
Step-by-step explanation:
Let the total numbers are n.
If the average of y numbers is x then we can form an equation

⇒ 
⇒ n =
--------(1)
Now 30 is added to the set of numbers then average becomes (x - 5)

⇒ 
⇒ (n + 1) = 
⇒ n =
- 1 ----- (2)
Now we equate the values of n from equation 1 and 2
=
- 1
y(x - 5) = x(y + 30) - x(x - 5) [ By cross multiplication ]
xy - 5y = xy + 30x - x² + 5x
xy - xy - 5y = 35x - x²
-5y = 35x - x²
x² - 35x = 5y
y = 
Answer:In general, any equation of the form ax + b = c, with a not equal to zero, can be solved in two steps. First add the opposite of b to both sides. Then multiply both sides by the reciprocal of a. x - 53 = 7.
Answer: The 18th term is 295.
Step-by-step explanation: By using the arithmetic sequence formula:
a(n): nth term
a(1): first term
n: term position
d: common/constant difference
a(n) = a(1) + (n - 1)d
You should get an equation of a(n) = 6+(18 - 1)17. By following the order of operations, you should receive an 18th term of 295.