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nekit [7.7K]
3 years ago
8

What is the relative frequency of adults with tickets? Round to the nearest hundredth, if needed. 0.34 0.46 0.63 0.74 A two way

table with columns titled has a ticket, does not have a ticket, total and rows titled child, adult, total. Row 1 has a ticket child 10, does not have a ticket child 3, and total child 13. Row 2 has a ticket adult 17, does not have a ticket adult 20, and total adult 37. Row 3 has a ticket total 27, does not have a ticket total 23, and total total 50.
Mathematics
1 answer:
ki77a [65]3 years ago
7 0
The answer is .34 I did the test
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Answer; length = 14 width = 10

Step-by-step explanation:

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\bold{\huge{\blue{\underline{ Solution}}}}

\bold{\underline{ We \: have \:given \: that, }}

  • <u>Distance </u><u>between </u><u>the </u><u>house </u><u>and </u><u>tower </u><u>is </u><u>3</u><u>5</u><u> </u><u>m</u>
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  • <u>The </u><u>height </u><u>of </u><u>the </u><u>house </u><u>is </u><u>2</u><u>5</u><u> </u><u>m</u>

\bold{\underline{ Now}}

  • <u> </u><u>Height</u><u> </u><u>of </u><u>the </u><u>house </u><u>is</u><u> </u><u>2</u><u>5</u><u>m</u>

\bold{\underline{ So, }}

\sf{ CE = 25m }

<u>Therefore</u><u>, </u>

\sf{ AB = AD - CE }

\sf{ AB = 60 - 25  }

\sf{ AB = 35 m }

<u>Now</u><u>, </u><u> </u><u>In </u><u>Right </u><u>angled </u><u>ABC</u>

\bold{tan Φ =}{\bold{\frac{ AB}{BC}}}

\bold{tan Φ =}{\bold{\frac{ 35}{35}}}

\bold{ tan Φ = 1 }

\bold{ tan Φ = 45 °}

\sf{\red{Hence, \: The \:angle \:of \:depression\: is \:45°}}

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Question 2: -4/3

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