Which statement is true?

June had $240 more than Siti. Junr gave 25% of her money to Siti. Siti then gave 20% of her money to June. How much more money d

bulgar [2K]

Answer:

$144

Step-by-step explanation:

Let the money which Siti has be x

Therefore, the money June has will be x+240

First condition is that June gave 25% of her money to Siti, So this amount will be deducted from June's money and will be added in Siti's money.

Siti's money = x+ [25%(x+240)] June's money = x+240-[25%(x+240)]

= 1.25x + 60 = 0.75x + 180

Second condition is that Siti now gave 20% of her money to June.This amount will be deducted form Siti's money and added in June's money.

Siti's money = 1.25x+60-[20%(1.25x+60)]

= x+48

June's money = 0.75x +180+[20%(1.25x+60)]

= x+192

Difference between Sitit and June's money = x+192-x-48

= 144

Hence, June has $144 more money than Siti.

4 0

3 years ago

Find the equation is standard form, of the line passing through he points (2,-3) and (4,2)

Simora [160]

The point slope formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

$(2,\ -3)\to x_1=2,\ y_1=-3\\(4,\ 2)\to x_2=4,\ y_2=2$

Substitute:

$m=\dfrac{2-(-3)}{4-2}=\dfrac{5}{2}=2.5\\\\y-(-3)=2.5(x-2)\\\\y+3=2.5x-5\ \ \ \ |+5\\\\y+8=2.5x\ \ \ \ \ \ |-y\\\\2.5x-y=8\ \ \ \ \ |\cdot2\\\\\boxed{5x-2y=16}$

5 0

3 years ago

Complete the square for 5x^2 – 30x = 5.

Yuri [45]

First, subtract 5 from both sides, leaving you with 5 $x^{2}$ - 30x - 5 = 0
If you use the quadratic formula (a=5), (b=-30), (c=-5)

x=-b +/- √b²-4ac / 2a

x= -(30) +/- √(30)² - 4(5) * (-5) / 2(5)

x= 30 +/- √1000 / 10

x = 3 +/- √10

7 0

3 years ago

Helpppppp asappppp plsssss

shusha [124]

Answer:

x = -2

Step-by-step explanation:

The segments described in the question are equidistant (meaning they are the same length). Therefore, using algebraic techniques, we can set these two equal to each other and solve for x.

4x - 8 = 6x - 4 Combine like terms by subtracting 6x from both sides.

-2x - 8 = -4 Combine like terms by adding 8 to both sides.

-2x = 4 Divide by -2 on both sides of the equation.

x = -2

6 0

3 years ago

A rectangle has sides measuring (6x + 4) units and (2x + 11) units. Part A: What is the expression that represents the area of t

valentinak56 [21]

Answer:

Step-by-step explanation:

Part A:

A=lw

A=(6x + 4)*(2x + 11)

multiply it out:

A=6x*2x+6x*11+4*2x+4*11

A=12x^(2)+66x+8x+44

add like terms

A=12x^(2)+66x+8x+44

A=12x^(2)+(66+8)x+44

A=12x^(2)+74x+44

the expression used to find area is 12x^(2)+74x+44

Part B:

this is:

a second degree trinomial

since its leading coefficient (highest degree value of the expression) is 2

and

since it has three monomials (terms that are separated by + or - signs):

12x^(2)+74x+44

Part C:

(not sure about this one)

all area is positive or 0 (no area), so lets find the values of x that are true:

lets find the zeros

(6x + 4)*(2x + 11)=0

6x+4=0

6x=-4

x=-4/6

x=-2/3

2x+11=0

2x=-11

x=-11/2

6*(-11/2)+4

3*(-11)+4

-33+4

-29

2*(-2/3)+11

-4/3+33/3

29/3

6*(-2/3) + 4

2*(-2)+4

-4+4

0

x is greater than (-2/3)

Thus, any real number greater than -2/3 makes

(6x + 4)*(2x + 11) equals the expression:

12x^(2)+74x+44, where x is a real number greater than -2/3

if lets say x= 1, a counting number then:

(6*1 + 4)*(2*1 + 11)=12*1^(2)+74*1+44

(6+4)*(2+11)=12*1+74+44

10*13=12+118

130=130

130 and 1 are both counting numbers, proving the closure property of polynomials

7 0

3 years ago

Read 2 more answers