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KATRIN_1 [288]
3 years ago
11

Each baseball team has nine players and each football team has eleven players. Six schools have both baseball and football teams

. Four schools have only a baseball team. How many players are there for all ten schools?
Mathematics
2 answers:
jolli1 [7]3 years ago
6 0
156 players in all ten schools
svetoff [14.1K]3 years ago
5 0
<span>Each baseball team has nine players and each football team has eleven players. Six schools have both baseball and football teams. Four schools have only a baseball team. How many players are there for all ten schools. The answer is 56 players. The six schools have 54 plus 66 players (baseball and football respectively ie 9x6 and 11x6) and the four schools have 9x4 =36 players so 54 + 66 +36= 156 players total.</span>
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Answer:

False

Step-by:-step explanation

2 million years

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martin can run 6 miles in 60 minutes. He wants to run in either one of two upcoming races, a 4 mile race or a 12 mile race. At h
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Do not round intermediate calculations. round your answers to two decimal places. a. define a random variable number of times th
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Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours

547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000

x = no. of times owner-occupied units had a water supply stoppage.

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x           f(x)

0             0.0370

1              0.3393

2         0.4137

3              0.1722

4         0.0378

Total     1

Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.

To learn more about the probability distribution visit:

brainly.com/question/24756209

#SPJ1

7 0
2 years ago
On Novenber 4, your bank statement shows a balance of $2,253.18. Your checkbook shows a balance of $2,324.34. If there are outst
ivann1987 [24]

Answer:

The final answer is "$2387.85 and $2594.85".

Step-by-step explanation:

Given values:

The bank statement balance= $2,253.18

The checkbook balance = $2,324.34

outstanding check amounts= $105.50 and $158.10

transit amount= $605.27

account earnin(credits)= $68.51

service charge= $5.00

Adjusted Checkbook Balance =?

Adjusted  Statement Balance=?

Adjusted the Checkbook Balance:

checkbook balance = $2,324.34

\text{total checkbook balance = checkbook balance+ credits}\\

                                      = \$ 2,324.34+ \$ 68.51\\\\= \$ 2392.85

\text{ Adjust check book balance= total checkbook balance - servicec  charge}

                                         = \$2392.85 - \$5.00\\\\= \$ 2387.85

Adjusted the Statement Balance:

bank statement balance= $2,253.18

\text{total Statement balance = bank  Statement balance+  transit amount}\\

                                      = \$ 2,253.18+ \$ 605.27\\\\= $ 2,858.45

\text{outstanding check amounts = $105.50+ $158.10}

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\text{ Adjust statement  balance= total statement balance - outstanding check amount }                                        = \$ 2,858.45 -  \$263.60\\\\= $ 2,594.85

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