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2 years ago

Find the GCF (greatest common factor) of the following terms. {5x2y2,25x3y2,x2y2}

Mathematics

2 answers:

HACTEHA [7]2 years ago

7 0

Answer:

5x2y2 is the GCF common factor of the following terms.

Nina [5.8K]2 years ago

7 0

The GCF is x^2 y^2.

Every term has at least x^2 built into it, as well as y^2. The last term only has a coefficient of 1, so 1 is the GCF for the coefficients.

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Marine scientists categorize signature whistles of bottlenose dolphins by typelong dash—type a, type b, type c, etc. In one s

r-ruslan [8.4K]

Answer:

The 95% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 185, \pi = \frac{100}{185} = 0.5405$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123$

The 95% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

3 0

3 years ago

9(2m + 5n + 10) =

Galina-37 [17]

Answer:

Step-by-step explanation:

9 multiple 2m = 18m

9 multiple 5n = 45n

9 multiple 10= 90

5 0

3 years ago

Read 2 more answers

Which equation can be used to solve the following word problem? Seth has 8 more nickels than dimes, and the total value of his c

9966 [12]

Answer:

Seth has 21 nickels

Step-by-step explanation:

Let n represent the number of nickels. Since Seth has 8 more nickels than dimes, then (n-8) is the number dimes.

Nickel is worth 5 cents and dime is worth 10 cents. Thus, n nickels are worth 5n cents and (n-8) dimes are worth 10(n-8) cents. The total value of Seth's coins is $2.35 that is 235 cents, then

$5n+10(n-8)=235.$