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nevsk [136]
2 years ago
7

Find the GCF (greatest common factor) of the following terms. {5x2y2,25x3y2,x2y2}

Mathematics
2 answers:
HACTEHA [7]2 years ago
7 0

Answer:

5x2y2 is the GCF common factor of the following terms.

Nina [5.8K]2 years ago
7 0
The GCF is x^2 y^2.

Every term has at least x^2 built into it, as well as y^2. The last term only has a coefficient of 1, so 1 is the GCF for the coefficients.
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Marine scientists categorize signature whistles of bottlenose dolphins by typelong dash—type ​a, type​ b, type​ c, etc. In one s
r-ruslan [8.4K]

Answer:

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 185, \pi = \frac{100}{185} = 0.5405

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

3 0
3 years ago
9(2m + 5n + 10) =
Galina-37 [17]

Answer:

B

Step-by-step explanation:

9 multiple 2m = 18m

9 multiple 5n = 45n

9 multiple 10= 90

5 0
3 years ago
Read 2 more answers
Which equation can be used to solve the following word problem? Seth has 8 more nickels than dimes, and the total value of his c
9966 [12]

Answer:

Seth has 21 nickels

Step-by-step explanation:

Let n represent the number of nickels. Since Seth has 8 more nickels than dimes, then (n-8) is the number dimes.

Nickel is worth 5 cents and dime is worth 10 cents.  Thus, n nickels are worth 5n cents and (n-8) dimes are worth 10(n-8) cents. The total value of Seth's coins is $2.35 that is 235 cents, then

5n+10(n-8)=235.

Solve this equation:

5n+10n-80=235,\\ \\15n=235+80,\\ \\15n=315,\\ \\n=21.

6 0
3 years ago
3x+2y=4 <br> 4x+5y=17<br> What is the value of x and y?
Fudgin [204]
{3x+2y=4    /*5
{4x+5y=17    /*(-2)

{15x+10y=20
<u>{-8x-10y=-34        </u>(+)
<em>7x=-14</em><em />
<em>x=-2</em>

15x+10y=20
15*(-2)+10y=20
-30+10y=20
10y=50
<em>y=5</em>

5 0
3 years ago
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Solve for x.<br><br> 7 - (2x + 11) + 3(3 - x) = 20
zvonat [6]

Answer:

your answer should be x = -3

7 0
3 years ago
Read 2 more answers
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