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mafiozo [28]
3 years ago
13

What is the area of triangle TUV?

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0

Answer:

B. 5.25 square units

Step-by-step explanation:

Use side TV as the base and The dashed vertical segment as the height.

base = b = 7

height = h = 1.5

area = bh/2

area = 7 * 1.5/2

area = 10.5/2

area = 5.25 square units

Answer: B. 5.25 square units

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In your own words tell how you can use the number line to add and subtract integers.
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Answer:

We can use number lines for adding as well as subtracting integers. For doing this:

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3. In case you have to add a negative integer, move to the left on the number line from this number.

4. Subtracting an integer means adding its opposite and hence, if you have to subtract a positive integer from this number, move to the left on the number line from this number.

5. But if you have to subtract a negative integer from this number, move to the right on the number line from this number.

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3 years ago
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yanalaym [24]
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Use the product of powers property to simplify the numeric expression.
motikmotik

Answer:

The value of 4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}  is  4^{\dfrac{8}{15}} .

Step-by-step explanation:

We need to simplify the numeric expression using property. The expression is as follows :

4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}

The property to be used is : x^a{\cdot} x^b=x^{a+b}

This property is valid if the base is same. Here, base is x.

In this given problem, x = 4, a = 1/3 and b = 1/5

So,

4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}}=4^{\dfrac{1}{3}+\dfrac{1}{5}}\\\\=4^{\dfrac{5+3}{15}}\\\\=4^{\dfrac{8}{15}}

So, the value of 4^{\dfrac{1}{3}} {\cdot} 4^{\dfrac{1}{5}  is  4^{\dfrac{8}{15}} .

8 0
4 years ago
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