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3 years ago

Help ?!-10+3x=8 X=??

2 answers:

8 0

Ok, so first off you need to remember that your goal is to get x alone.
How do you do this? Well, let's get rid of that pesky negative ten, shall we?
The opposite of a negative is positive, so you can move negative ten to the other side of the problem by adding ten. Make sure that you do operations on both sides. Once you add, you have 3x=18. When a number is right next door to an x, it means it is being multiplied. To get rid of the three, divide by three on both sides. Now your get x=6, which is your answer. Hopefully, I explained this well! :D

AlexFokin [52]3 years ago

4 0

X-10+3x=8 what you do to one side you do to the other.
-3 -3 to undo the addition you subtract, so you subtract 3 from one
5 side of the equation and the other so 8-3=5 then the 3 that you
x-10=5 subtracted it cancels so you drop down what is left which would
+10 +10 be x-10=5 so you add 10 on both sides to undo the subtraction
x=15 the the 10 you subtracted it cancels so 10+5=15 so x=15.
i tried to explain as well as i could so yea hope you understand.

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vekshin1

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90 / 1800 = 0.05

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3 years ago

Help pls with 10 and 11

Alex

10
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3 years ago

A positive number is 30 less than its square. Find the number.

Veronika [31]

<span><span>x = x^2 - 30

or

x^2 - x - 30 = 0
Factors to
(x-6)(x+5) = 0

x = +6 is the positive number</span></span>

8 0

3 years ago

One more time!

CaHeK987 [17]

Since q(x) is inside p(x), find the x-value that results in q(x) = 1/4

$\frac{1}{4} = 5 - x^2\ \Rightarrow\ x^2 = 5 - \frac{1}{4}\ \Rightarrow\ x^2 = \frac{19}{4}\ \Rightarrow \\
x = \frac{\sqrt{19} }{2}$

so we conclude that
$q(\frac{\sqrt{19} }{2} ) = 1/4$

therefore

$p(1/4) = p\left( q\left(\frac{ \sqrt{19} }{2} \right) \right)$

plug $x=\sqrt{19}/2$ into p( q(x) ) to get answer

$p(1/4) = p\left( q\left( \frac{ \sqrt{19} }{2} \right) \right)\ \Rightarrow\ \dfrac{4 - \left( \frac{\sqrt{19} }{2}\right)^2 }{ \left( \frac{\sqrt{19} }{2}\right)^3 } \Rightarrow \\ \\ \dfrac{4 - \frac{19}{4} }{ \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{8\left(4 - \frac{19}{4}\right) }{ 8 \cdot \frac{19\sqrt{19} }{8}} \Rightarrow \dfrac{32 - 38}{19\sqrt{19}} \Rightarrow \dfrac{-6}{19\sqrt{19}} \cdot \frac{\sqrt{19}}{\sqrt{19}}\Rightarrow$

$\dfrac{-6\sqrt{19} }{19 \cdot 19} \\ \\ \Rightarrow -\dfrac{6\sqrt{19} }{361}$

$p(1/4) = -\dfrac{6\sqrt{19} }{361}$

3 0

3 years ago

In the number 340.79 , the 0 is in what place

kirill115 [55]

Answer:

units

Step-by-step explanation:

The zero (0) is in the units place. unit = 1

4 0

3 years ago

Read 2 more answers