Answer:
Step-by-step explanation:
25m - 100 = 450
25m = 450 + 100
25m = 550
m = 550/25
m = 22 <==== 22 months
An algebraic expression to represent the value of this car after M months is y=Mx+C.
We have given that the
The straight-line depreciation equation for a car is,
y = -2,680x + 26,800.
therefore after 4moths
y = -2,680(4) + 26,800.
y = -10720 + 26,800.
y=16080
<h3>
What is the slope?</h3>
The slope of a line is a measure of its steepness. Mathematically, the slope is calculated as rise over run (change in y divided by change in x)
b. For find after the 75 months replace x by 75 and slolve the given inequality.
Suppose that M represents the length of time in months when
the car still has value.
An algebraic expression to represent the value of this car after M months.
y=Mx+C.
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You can substitute it for 5.
2/5 = 0.4 = 40%
5/10 = 0.5 =50%
Hi <span>Officiallylilly!
So 207 students in 9 classes, how many are in 6 classes? OK this is easy to solve so we do 207/9 to find out how many is in one class which is 23 in one class. Ok so if 23 is one class now we need to find out how many is in 6 classes which all we do is 23*6 which is 138.
Hope this helps!</span>
20 × 10 to the 3rd power is 10000
