Answer:
x = 20
y = 10
m∡8 = 110°
Step-by-step explanation:
m∡1 + m∡2 = 180
5x + y + 3x + y = 180
8x + 2y = 180
m∡1 = m∡8 (they are alternate-exterior angles and are congruent)
5x + y = 3x + 5y
2x = 4y
x = 2y
Substitute '2y' for 'x' in 8x + 2y = 180
8(2y) + 2y = 180
18y = 180
y = 10
x = 2(10)
x = 20
m∡8 = 3(20) + 5(10) = 110°
K is whatever you want it to be
Answer: the intersection of plane A and plane S will be: line CW
the intersection of lines N and K is: point V
point X is the intersection of: line M and plane A
Step-by-step explanation:
(a)
Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points. It's in the first bar so we can estimate Q1=5. In reality the bar includes values from 0 to 9 or 10 (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.
The median is bigger than half the points. First bar is 37%, next is 22%, so its about halfway in the second bar, median=15
Third bar is 11%, so 70% so far. Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40
b
When the data is heavily skewed left like it is here, the median tends to be lower than the mean. The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.
