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LekaFEV [45]
4 years ago
13

One number is 2 more than 3 times another. their sum is 22. find the numbers.

Mathematics
2 answers:
kramer4 years ago
8 0
This question is asking for the value of two numbers, which we can label as:

#1 = x
(Any value we do not know can be represented with a variable)
#2 = 3x + 2
("2 more" means + 2, and "3 times" means multiply by 3. The "another" is the variable we talked about before. Combining everything we have 3x + 2).

The last piece of information we are given is that the sum of the two numbers is 22. The word sum indicates that we need to add the two numbers, and when they added they will equal the integer 22.
(x) + (3x + 2) = 22
x + 3x + 2 = 22
Combine like terms
4x + 2 = 22
Subtract 2 from both sides
4x = 20
Divide 4 from both sides
x = 5

This sole value of "x" already gives us the value of the first number. Since our second number is "3x + 2", all we have to do is plug in the value of x into the expression.

3x + 2 = 3(5) + 2 = 15 + 2 = 17
The second number is 17.

Final Answer: The two numbers are 5 and 17.
(If you want to check, add the two numbers and make sure they add up to 22 and multiply 5 by 3 and add 2.)

viktelen [127]4 years ago
4 0
X+3x+2=22
4x=20
x=5
3x+2=17
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Answer the following
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The set A satisfying the given inequality is A = (-\infty, -10].

<h3>What are some properties of an inequality relation? </h3>

Following are some facts which are true for an inequality relation:

  • Equal numbers can be added or subtracted from both sides of an inequality without affecting the inequality sign.
  • The Inequality sign is unchanged if both sides are multiplied or divided by a positive number, but when multiplied or divided by a negative number the inequality sign is reversed.

\frac{5x-2}{8} - \frac{3x-5}{10} &\ge& x+y\\\\\Rightarrow\;\; \frac{13}{40}x + \frac{1}{4}&\ge& x+y\\\\\Rightarrow\;\;\;\;\;\; -\frac{27}{40}x &\ge & y - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\;\; -x &\ge & \frac{40}{27}\left( y-\frac{1}{4} \right).\hspace{1cm}(1)

Since y ∈ B, -2 ≤ y ≤ 7. So,

\;\;\;\;\;\;\;\,-2 - \frac{1}{4}\; \le\; y - \frac{1}{4} \;\le\; 7 - \frac{1}{4}\\\\\Rightarrow\;\;\;\;\;\;\;\;\; -\frac{9}{4}\; \le\;  y - \frac{1}{4} \;\le\; \frac{27}{4}\\\\\Rightarrow\;\;\; -\frac{9}{4}\cdot \frac{40}{27} \;\le\; \frac{40}{27} \left( y-\frac{1}{4} \right) \;\le \;\frac{27}{4}\cdot \frac{40}{27}\\\\\Rightarrow\;\;\;\;\;\;\;\; -\frac{10}{3} \;\le\; \frac{40}{27}\left( y - \frac{1}{4} \right)\; \le\; 10.

The set {-x | inequality (1) holds ∀ y ∈ B} is [10, \infty) i.e.

10 ≤ -x ≤ \infty.

Multiplying -1 throughout gives

-10 ≥ x ≥ -\infty.

x, thus, lies in the range A = (-\mathbf{\infty}, -10}.

Learn more about the inequality here.

brainly.com/question/17801003

Disclaimer: The question was incomplete. Please find the full content below.

<h3>Question </h3>

Find the set A such that for x ∈ A

\frac{5x - 2}{8} - \frac{3x - 5}{10} \ge x + y

∀y ∈ B = {y ∈ R | -2 ≤ y ≤ 7}.

#SPJ4

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