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zzz [600]
3 years ago
15

How do i solve this problem

Mathematics
1 answer:
xeze [42]3 years ago
6 0
Split the figure into a trapezoid and a triangle

Area of trapezoid = 1/2(b1+b2) h
= 1/2(2 +6) * 4
= 2(8)
= 16 in^2

Area of triangle = 1/2 bh
= 1/2(6)(3)
= 9 in^2

Area of figure = Area of trapezoid + Area of triangle
= 16  in^2 + 9  in^2
= 25  in^2

Answer:
C.  25 square inches
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A student number system for a county requires that the student number be 5 characters.
Radda [10]

Answer:

131040

Step-by-step explanation:

10*9*8*7*26

=131040

5 0
2 years ago
Find the vertex of this function <br> f(x)= x^2+4x-12
sergij07 [2.7K]
F(x) = x² + 4x - 12

x = -b/2a
x = -(4)/2(1)
x = -4/2
x = 2

f(x) = x² + 4x - 12
f(2) = (2)² + 4(2) - 12
f(2) = 4 + 8 - 12
f(2) = 12 - 12
f(2) = 0

The vertex of the function is (2,0).
7 0
3 years ago
Use the information provided to write the equation of each circle​
Nadusha1986 [10]

Answer:

1.

centre(h,k)=(-13,9)

radius (r)=6

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x+13)²+(y-9)²=6²

x²+26x+169+y²-18y+81=36

x²+y²+26x-18y+169+81-36=0

x²+y²+26x-18y +214=0

is a required equation of the circle.

2.

centre(h,k)=(1,-1)

radius (r)=11

we have

equation of the circle is

(x-h)²+(y-k)²=r²

(x-1)²+(y+1)²=11²

x²-2x+1+y²+2y+1=121

x²+y²-2x+2y=121-2

x²+y²-2x+2y=119

is a required equation of the circle.

4 0
2 years ago
CAN SOMEONE PLEASE HELP ME DO THE EQUATION
valina [46]

y=2/5x


5y=2x

so y=2x÷5=2/5x

7 0
3 years ago
(15 − 3) ÷ (2 + 1) × (8 − 6)
Law Incorporation [45]

Step-by-step explanation:

= (15 − 3) ÷ (2 + 1) × (8 − 6)

BODMAS rule

= (12) ÷ (3) × (2)

= (12/3) × (2)

= 4 × 2

= 8

Hope this helps you. Do mark me as brainliest.

6 0
3 years ago
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