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arlik [135]
3 years ago
14

Can some one help, step bye step please

Mathematics
2 answers:
il63 [147K]3 years ago
4 0

Answer:

$14.23

Step-by-step explanation:

Multiply the original value by 1.035 to get your answer.

Thepotemich [5.8K]3 years ago
3 0

Let x be the initial salary

x=13.75

Let y be the new salary

y=x+x(3.5%)

y=13.75+13.75(0.035)

y=13.75+0.48=14.23

New hourly salary=14.23$

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The Earth's circumference measured at the equator is approximately 1.3148 × 108 feet. What is the number written in standard for
maks197457 [2]

Answer:

The number written in standard form is 131,480,000

Step-by-step explanation:

we have

1.3148*10^8

we know that

10^8=100,000,000

substitute

1.3148*10^8=1.3148(100,000,000)

Remember that

When multiplying decimals by 10, move the decimal point one space to the right

In this case move the decimal point eight spaces to the right

1.3148(100,000,000)=131,480,000

therefore

The number written in standard form is 131,480,000

4 0
3 years ago
Please help me
SVETLANKA909090 [29]

Answer:

B-$100=$372

The is is the smartest way I could look at this

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$372 - $100= b

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5 0
3 years ago
Please help me with maths !!!
zlopas [31]

Answer:

  • 170.7 cm

Step-by-step explanation:

Let the original water level is x.

<u>Use below equation to find its value:</u>

  • x + 2.4 + 3 1/2 = 162 + 14.6
  • x + 2.4 + 3.5 = 176.6
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3 0
3 years ago
_______x (-4) = 48.
Zinaida [17]

Answer:

-12

Step-by-step explanation:

you have to divide 48 to (-4) and it equals to -12

so you multiply -12 to (-4) and it gives you 48

3 0
3 years ago
Helpppppppppppppppppppppp..... .......<br><br><br>​
morpeh [17]

Answer:

{ \sf{( \sec \theta -  \csc \theta)(1 +  \tan \theta +  \cot \theta) }} \\  = { \sf{( \sec \theta +  \tan \theta \sec \theta +  \cot  \theta \sec  \theta) - ( \csc  \theta -   \csc \theta \tan  \theta -  \csc \theta \cot  \theta)}} \\  = { \sf{( \sec \theta +  \sec \theta \tan  \theta +  \csc  \theta) - (  \csc  \theta -  \sec \theta -  \csc  \theta \cot   \theta)}} \\  = { \sf{ \sec  \theta \tan  \theta +  \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}

3 0
3 years ago
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