Construct a 99% confidence interval for life expectancy of a new GE light bulb. 64 bulbs are randomly selected and a mean of 750
hours and a standard deviation of 20 hours is found. Assume the distribution of life expectancy is normally distributed.
1 answer:
Construct a 99% confidence interval for life
expectancy of a new GE light bulb:<span>
n = 64
Xbar = 750
s.d. = 20
Critical z value at 99% confidence = 2.576
margin of Error, E = 2.576*20/√64 = 6.44
<span>99% confidence interval for life expectancy of a
new GE light bulb = (Xbar - E; Xbar + E) = (743.56; 756.44)</span></span>
You might be interested in
Theyre all labeled correctly, what exactly is the question?
Answer:
a=4, k=2, and b= -pi/4
Step-by-step explanation:
<3
Answer:
lkfklfkkfjfjdfklfklfklfkfdkfdkldf
Step-by-step explanation:
Use the midpoint formula it’s pretty straightforward from there. (-4.5 , -2)
Answer:
x= -1/2
Step-by-step explanation:
-3/4x+9/4-5=1/8x-1/8
-3/4x-11/4=1/8x-1/8
x=9/4-11/4
x=-1/2
