Construct a 99% confidence interval for life expectancy of a new GE light bulb. 64 bulbs are randomly selected and a mean of 750
hours and a standard deviation of 20 hours is found. Assume the distribution of life expectancy is normally distributed.
1 answer:
Construct a 99% confidence interval for life
expectancy of a new GE light bulb:<span>
n = 64
Xbar = 750
s.d. = 20
Critical z value at 99% confidence = 2.576
margin of Error, E = 2.576*20/√64 = 6.44
<span>99% confidence interval for life expectancy of a
new GE light bulb = (Xbar - E; Xbar + E) = (743.56; 756.44)</span></span>
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