3(x + 1) - 2x = -6 |use distributive property: a(b + c) = ab + ac
3x + 3 - 2x = -6
x + 3 = -6 |subtract 3 from both sides
x = -9
Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
</span>
Answer:
5
Step-by-step explanation:
( divide numerator and denominator by 5 ) , then
= 
( with missing number ? = 5 )
5:
1/2 , 3/5 , .606 , 13/20 , 66%
6:
0.09 , 1/10 , 12% , .13 , 3/20
The answers to the questions are C=11 and D=3
