3 years ago

Help thx so much for ur help

1 answer:

yan [13]3 years ago

6 0

Answer:

351.33

Step-by-step explanation:

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valina [46]

If $W$ is a random variable representing your winnings from playing the game, then it has support

$W=\begin{cases}43&\text{if you draw something with value at most 3}\\-11&\text{otherwise}\end{cases}$

There are 52 cards in the deck. Only the 1s, 2s, and 3s fulfill the first condition, so there are 12 ways in which you can win $43. So $W$ has PMF

$P(W=w)=\begin{cases}\frac{12}{52}=\frac3{13}&\text{for }w=43\\1-\frac{12}{52}=\frac{10}{13}&\text{for }w=-11\\0&\text{otherwise}\end{cases}$

You can expect to win

$E[W]=\displaystyle\sum_ww\,P(W=w)=\frac{43\cdot3}{13}-\frac{11\cdot10}{13}=\boxed{\frac{19}{13}}$

or about $1.46 per game.

3 0

3 years ago

Aliun [14]

I believe the answer is 267

If each is worth $25 and it costs $10 then he is making $15 profit.

4000/15 is 266.6666667

So you would need 267

8 0

3 years ago

Elanso [62]

Answer: D. all real numbers less than or equal to –3

5 0

3 years ago

schepotkina [342]

y=-2x+5

Hope that helps :D

4 0

4 years ago

Helen [10]

2x+y=8 is the equation perpendicular to x-2y=8.

6 0

3 years ago