Answer:
B 12.68
Step-by-step explanation:
you will need to find the distance between each segment-
so the length of DC, CF, FE, ED

DC:
D(-2,-1) C(-1,2)

CF:
C(-1,2) F(1,1)

FE
F(1,1) E(2,-2)

ED
E(2,-2) D(-2,-1)

3.16+2.24+3.16+4.12= 12.68
Answer:
(-x,-y)
Step-by-step explanation:
I checked inside the module where I learned it. So, I’m pretty sure this is the right answer.
Because it is a 90° angle and the legs are congruent, the legs intersect with the hypotenuse at the same angle, so the other, unnamed angle at the bottom left is equal to x.
Now we can state that:
2x + 90 = 180
2x = 90
x = 45
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
Answer:
15,9,8 can be divided by 3
so, the greatest number of fruit in each basket is 3 Step-by-step explanation: