Answer:
6 hearts to 9 stars
Step-by-step explanation:
Answer:
prove that:
Sin²A/Cos²A + Cos²A/Sin²A = 1/Cos²A Sin²A - 2
LHS = \frac{Sin^2A}{Cos^2A} + \frac{Cos^2A}{Sin^2A}
Cos
2
A
Sin
2
A
+
Sin
2
A
Cos
2
A
= \begin{lgathered}= \frac{Sin^4A + Cos^4A}{Cos^2A . Sin^2A}\\\\Using\: a^2 + b^2 = (a+b)^2 - 2ab\\\\a = Cos^2A \: \& \:b = Sin^2A\\\\= \frac{(Sin^2A + Cos^2A)^2 - 2Sin^2A Cos^2A}{Cos^2A Sin^2A} \\\\Sin^2A + Cos^2A = 1\\\\= \frac{1 -2Sin^2A Cos^2A}{Cos^2A Sin^2A}\end{lgathered}
=
Cos
2
A.Sin
2
A
Sin
4
A+Cos
4
A
Usinga
2
+b
2
=(a+b)
2
−2ab
a=Cos
2
A&b=Sin
2
A
=
Cos
2
ASin
2
A
(Sin
2
A+Cos
2
A)
2
−2Sin
2
ACos
2
A
Sin
2
A+Cos
2
A=1
=
Cos
2
ASin
2
A
1−2Sin
2
ACos
2
A
\begin{lgathered}= \frac{1}{Cos^2A Sin^2A} - 2\\\\= RHS\end{lgathered}
=
Cos
2
ASin
2
A
1
−2
=RHS
LHS=RHS
<h3>
Answer: x = 7</h3>
Explanation:
Segment addition postulate
CD+DE = CE
this basically is the idea of gluing smaller pieces together to get a larger structure. We can go in reverse to break up a large item into smaller bits. This is assuming there is no leftovers, overlaps, or parts wasted/lost.
CD = 9
DE = 3x+6
CE = 36
----
CD+DE = CE
9+3x+6 = 36
3x+15 = 36
3x = 36-15
3x = 21
x = 21/3
x = 7
-----
If x = 7, then
DE = 3x+6 = 3*7+6 = 21+6 = 27
and
CD+DE = 9+27 = 36 = CE
confirming our answer
At x = 8, y = 4
At x = 14, y = 7
At y = 3, x = 6
Solution:
Given rule:
At x = 8,
Hence at x = 8, y = 4.
At x = 14.
Hence at x = 14, y = 7.
At y = 3
Multiply by 2 on both sides.
Hence at y = 3, x = 6.
The image of the table is attached below.
