Answer: b. 8.56 to 21.44
Step-by-step explanation:
Let 
be the mean number of pushups that can be done.
As per given , we have
Sample size : n= 10
Degree of freedom = n-1=9
Sample mean : 
Sample standard deviation : 
Significance level : α=1-0.95=0.05
From t- distribution table ,
Critical two -tailed t-value for α=0.05 and df = 9 is
Confidence interval for is given by :-
Hence, the 95% confidence interval for the true mean number of pushups that can be done is 8.56 to 21.44.
Answer:
3 dollars and 60 cents
Step-by-step explanation:
Answer:
Step-by-step explanation:
x=0 and y=-2
Answer:
option A
Step-by-step explanation:
option A is the correct answer of this question.
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First, we want to find the GCF of 15 and 21, which is 3. Now we do 15 divided by 3 and 21 divided by 3, which gives us 5 and 7. To rewrite the expression, we take the GCF and put it on the outside of the parenthesis. Inside the parenthesis, we put 5 + 7. So it'll look like this:
3(5 + 7)
