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3 years ago

What are the coordinates of the center and length of the radius of the circle whose equation is X^2+6x+4y=23?

Mathematics

1 answer:

Virty [35]3 years ago

3 0

Answer:

The following equation is not a circle, but a hyperbola, because you have 4y, but no y^2

Step-by-step explanation:

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-3x + 5x +-3= 4x + 5x

Bingel [31]

Answer: -3/7

Step-by-step explanation:

-3x + 5x +-3= 4x + 5x

7x=-3

x=-3/7

8 0

2 years ago

Read 2 more answers

What are the first five terms in the recursive sequence defined by the following?

kolezko [41]

The first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

<h3>Recursive function</h3>

Given the nth term of a recursive expression shown below

an =an-1 - 1.4

where

an-1 is the preceding term

a1 is the first term

an is the nth term

an-1 is

Given the following

a1 = 0

For the second term a2

a2 = 0 - 1.4

a2 = -1.4

For the third term a3

a3 = -1.4 - 1.4

a3 = -2.8

For the fourth term a4

a4 = -2.8 - 1.4

a4 = -4.2

For the fifth term a2

a5 = -4.2 - 1.4

a5 = -5.6

Hence the first five terms of the sequence are {0, -1.4, -2.8, -4.2, -5.6}

Learn more on recursive function here: brainly.com/question/489759

#SPJ1

5 0

1 year ago

A class has 35 students, of which 16 are male and 19 are female. If 6 of the students are selected at random to form a committee

madreJ [45]

Answer:

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

Step-by-step explanation:

We are given that a class has 35 students

Number of male=16

Number of female=19

We have to choose 6 students for committee

We have to find the probability that exactly 2 male students are selected

Probability=P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

If we have to choose total 6 student in which 2 male and 4 female

Combination formula:

$nC_r=\frac{n!}{r!(n-r)!}$

Using the formula

The probability of choosing exactly 2 male and 4 female students = $\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}$

5 0

2 years ago

A group of people were asked if they had run a red light in the last year. 315 responded "yes", and 190 responded "no".

Iteru [2.4K]

Answer:

0.624

Step-by-step explanation:

Number who have run a red light = 315

Number who haven't run a red light = 190

From the data :

The total number of people sampled = total possible outcome = (315 + 190) = 505

Selecting a person at random, probability that the selected person has run a red light :

P = required outcome / Total possible outcomes

Required outcome = Number who have run a red light = 315

P(having run a red light) = 315 / 505 = 0.624

6 0

3 years ago

Item 1 A bag contains 7 blue cards, 4 green cards, 6 red cards, and 8 yellow cards. You randomly choose a card. a. How many poss

egoroff_w [7]

Answer:

4 possible outcomes

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.

The size of the sample space is the total number of possible outcomes

The event space is the number of outcomes in the event you are interested in.

Let

x------> size of the event space

y-----> size of the sample space

$P=\frac{x}{y}$

In this problem

The probability of choose a blue card is

$x=7$

$y=7+4+6+8=25$

substitute

$P=\frac{7}{25}$

The probability of choose a green card is

$x=4$

$y=7+4+6+8=25$

substitute

$P=\frac{4}{25}$

The probability of choose a red card is

$x=6$

$y=7+4+6+8=25$

substitute

$P=\frac{6}{25}$

The probability of choose a yellow card is

$x=8$

$y=7+4+6+8=25$

substitute

$P=\frac{8}{25}$

The sum of the probabilities of the 4 possible outcomes is equal to

$\frac{7}{25}+\frac{4}{25}+\frac{6}{25}+\frac{8}{25}=\frac{25}{25}$ ----> represent the 100%

4 0

3 years ago