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4 years ago

4 2/3 divided by 2 2/9

1 answer:

3 0

First, make improper fractions

4 2/3 = 14/3

2 2/9 = 20/9

Then divide

14/3 ÷ 20/9 = 14/3 * 9/20

= 126/60

Then simplify

= 2 1/10

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What is the slope of the line passing through the points (6, 7) and (1, 5) ?

neonofarm [45]

Answer:

-2/-5

none of the option is correct

6 0

3 years ago

A company conducted a survey to see whether its new toothpaste was morepopular with children or adults. Of the children surveyed

Naily [24]

Given: The information provided in the table shown

To Determine: From the options provided, the correct option that best describe the information given in the table

Solution

Given that 28% of the children used toothpaste. From the table

$Children(toothpaste)=\frac{0.07}{0.25}=\frac{7}{25}\times100=28\%$

Let us calculate the percentage of adult that used toothpaste

$Adult(toothpaste)=\frac{0.08}{0.75}=\frac{8}{75}\times100=10.667\%\approx11\%$

Hence, a smaller percentage of adults (about 11%) use the toothpaste.

The correct option is OPTION C

4 0

2 years ago

Passes through (-4, -5), slope = 3/4

ra1l [238]

Answer:

Step-by-step explanation:

y+5 = ¾(x+4)

4 0

3 years ago

PLEASEE HELPPPP!!! ahhhhh

Agata [3.3K]

(1,5)

To find this, do the opposite of how you got to (4,5).

Move right 2 units instead of left.

Move left 5 units instead of right.

Now, your on the point (1,5).

To check this, do what they said. (Move left 2 units and right 5 units) If its correct you end up on (4,5)

8 0

3 years ago

Determine the graph of the polar equation r=4/(1-1/2cosx(theta))

crimeas [40]

Answer:

see below

Step-by-step explanation:

We assume you want the graph of ...

$r=\dfrac{4}{1-\frac{1}{2}\cos{(\theta)}}$

A graphing calculator or spreadsheet is useful for this.

You know cos(θ) = cos(-θ), so the graph is symmetrical about the x-axis. You can evaluate the function at a few points to find the general outline.

r at 0° = 8

r at 30° ≈ 7.05

r at 45° ≈ 6.19

r at 60° ≈ 5.33

r at 90° = 4

r at 120° = 3.2

r at 135° ≈ 2.96

r at 150° ≈ 2.79

r at 180° ≈ 2.67

6 0

3 years ago