9. 10^42
10. 59049 x 2^36
11. 12^28
12. 1.85302019 x 10^15
13. 2^11
14. 1/2
15. -1
answer.
Answer:
x=2 and y=0 is the required result.
Step-by-step explanation:
We have been given system of equations:
5x+2y=105x+2y=10 (1)
And 3x+2y=63x+2y=6 (2)
We will use elimination method:
Multiply 1st equation by 3 and 2nd equation by 5 we get:
15x+6y=3015x+6y=30 (3)
15x+10y=3015x+10y=30 (4)
Now subtract (4) from (3) we get:
-4y=0−4y=0
y=0y=0
Now, put y=0 in (1) equation:
5x+2(0)=105x+2(0)=10
5x=105x=10
x=2x=2
Hence, x=2 and y=0
Answer:
-3x-y=10
Step-by-step explanation:
y+4=-3(x+2)
y+4=-3x-6
y=-3x-6-4
y=-3x-10
-3x-y=10
Answer:
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Step-by-step explanation:
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