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3 years ago

PLEASE HELP?!?!?!?!?!?!?!

Mathematics

1 answer:

Readme [11.4K]3 years ago

8 0

The surface area is 72 ft.^2.

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What is the area of the composite figure?

mars1129 [50]

Answer:

34.9^2

Step-by-step explanation:

Well if one side is 4 cm then the square is 16cm^2.

The area of a circle is pi r^2.

So the radius is 2.

we plug 2 in.

pi 4

12.6/2

6.3

6.3 * 3 = 18.9cm^2

18.9 + 16 = 34.9

5 0

3 years ago

A square ceiling has a diagonal of 23 ft. Shelton wants to put molding around the perimeter of the ceiling. The molding is sold

Hatshy [7]

Answer:

Minimum 66 feet of molding that he needs.

Step-by-step explanation:

Given that a square ceiling has a diagonal of 23 ft.

If the sides of the square ceiling are 'a' feet, then applying Pythagoras Theorem we can write, a² + a² = 23²

⇒ 2a² = 23²

⇒ a = 16.2634 feet (Approximate)

Now, the perimeter of the square ceiling will be 4a = 65.05 feet.

If the cost of molding along the perimeter of the ceiling is in per foot, then a minimum of 66 feet of molding that he needs. (Answer)

6 0

3 years ago

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ivanzaharov [21]

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Step-by-step explanation:

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4 0

2 years ago

Given the graph of the function F(x) below, what happens to F(x) when x is a

deff fn [24]

Answer:

Step-by-step explanation:

From the graph as x gets larger and becomes positive f(x) approaches 0 so the answer is C.

8 0

3 years ago

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago