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drek231 [11]
2 years ago
5

Hi, help me please solve this task 10 10 10 10=4 what should I put +-*:?

Mathematics
1 answer:
natima [27]2 years ago
3 0
Um it's definitely *
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Find the midpoint of the segment with the following endpoints. (5,3) and (1,9)
OLEGan [10]

Answer:

(3, 6)

Step-by-step explanation:

If you create a mini graph, like I did, you would have seen that the middle point is at the co-ordinates (3,6). I have attached a image to this reply, with my "graph". (Sorry if its a little ugly, but that doesn't matter, the math does.)

8 0
2 years ago
If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term​
Klio2033 [76]

Answer:

see explanation

Step-by-step explanation:

The common difference d of an arithmetic sequence is

d = a_{2} - a_{1} = a_{3} - a_{2}

Substitute in values and solve for k, that is

5k - 1 - 2k = 6k + 2 - (5k - 1)

3k - 1 = 6k + 2 - 5k + 1

3k - 1 = k + 3 ( subtract k from both sides )

2k - 1 = 3 ( add 1 to both sides )

2k = 4 ⇒ k = 2

--------------------------------------------------------

The n th term of an arithmetic sequence is

a_{n} = a_{1} + (n - 1)d

a_{1} = 2k = 2 × 2 = 4 and

d = 5k - 1 - 2k = 3k - 1 = (3 × 2) - 1 = 5

Hence

a_{8} = 4 + (7 × 5) = 4 + 35 = 39

4 0
3 years ago
Would someone help me 2/3 2/1 8/9 7/9 breast to least​
Tema [17]

Answer:

First of all, it's the Greatest to least! Second of all, 2/1, 8/9, 7/9, and 2/3.

Step-by-step explanation:

2/1 is 2, 8/9 is 1 more ninth than 7/9, and 2/3 is less third than 1.

4 0
2 years ago
Read 2 more answers
How do you write this in standard form 2x+3y=12
Akimi4 [234]
To get y by itself subtract 2x from both sides. The left side becomes 3y=12-2x. Then divide by 3 on both sides to get y by itself. Which you get y=4-(2/3)x

6 0
2 years ago
If you had an individual who was gifted and talented in math, and well above the rest of your class, how might you use different
irakobra [83]

Answer:

See explanation below.

Step-by-step explanation:

Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.

A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.

Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.

Hope this helps! Have an Awesome Day!! :-)

6 0
3 years ago
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