$f(x)=3x^2+x\\f(a)=3a^2+a\\f(4)=3*4^2+4=52\\\\f(x)-f(4)=3x^2+x-52=(x-4)(3x+13)\\\\\dfrac{f(x)-f(4)}{x-4} =\dfrac{3x^2+x-52}{x-4} \\\\if\ x \neq 4\ then \\\\\dfrac{f(x)-f(4)}{x-4} =\dfrac{(x-4)(3x+13)}{x-4} \\\\=3x+13\\$

6 0

3 years ago

Read 2 more answers

(HELP!!!) Please Factor Completely: <br> 9x^2y^2-27x^2y-72y^2+216y

Olegator [25]

Answer:

Can u space them out so i know which ones are exponents

Step-by-step explanation:

4 0

2 years ago

3/4 (x-12)=12<br> And 3/4y-12=12

lianna [129]

3/4 (x-12)=12
3/4x - 9= 12
+9 +9
3/4x=21
*3/4 *3/4
x= 15 3/4

and

3/4y-12=12
+12 +12
3/4y = 24
*3/4 *3/4
y= 18

5 0

3 years ago

Read 2 more answers