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2 years ago

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Solve: XC - XV. Show your answer as a Roman Numeral. Standard Roman Number Numeral 1 1 5 V 10 Х 50 L 100 С C 500 D 1,000 M OA) V

OB) VI OC) VII

1 answer:

Keith_Richards [23]2 years ago

6 0

Answer:

5,6,7

Step-by-step explanation:

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

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Marizza181 [45]

The diameter is 4 inches.

6 0

3 years ago

An ice cream cone has a diameter of 4.2 cm and a height of 11.5 cm. What is the volume of the cone? A. 18.6 cm³ B. 53.1 cm³ C. 2

777dan777 [17]

Answer:

B. 53.1 cm³

Explanation:

$\sf volume \ of \ cone: \dfrac{1}{3} \pi r^2h \ \ \ \ (r \ is \ radius, \ h \ is \ height)$

Here Given:

height: 11.5 cm

diameter: 4.2 cm

radius: d/2 = 4.2/2 = 2.1

Volume:

$\sf \cdot \ \dfrac{1}{3} \pi r^2h$

$\sf \cdot \ \dfrac{1}{3} (3.14) (2.1)^2(11.5)$

$\sf \cdot \ 53.11 \ cm^3$ ≈ $\sf 53.1 \ (rounded \ to \ nearest \ tenth)$

6 0

2 years ago

I need help on this asap thanks

lina2011 [118]

1st find the averages of each one:

Elizabeth average of reading in min =(18+36+15+45+88+57+12)/7 =38.71 min

Sam average of reading in min =(17+52+48+35+13+71+16)/7 =36 min

question:

1) No
2) YES. [the range is te difference between the largest & the smallest)
Eliz Range = 88-12 =76 & Sam's= 71-13 = 58

3) NO. Sam 71 min & Eliz 88 min

4) YES. Median Eliz =45 min. Median Sam =35 min

4 0

3 years ago

The United States Marine Corps is reviewing its orders for uniforms because it has a surplus of uniforms for tall men recruits a

Vlad [161]

Answer:

$69.7 -2.58 \frac{2.8}{\sqrt{772}}=69.44$

$69.7 +2.58 \frac{2.8}{\sqrt{772}}=69.96$

And we can conclude that the true mean for the heights of mens between the ages of 18 to 24 is between 69.44 and 69.7 inches.

Step-by-step explanation:

For this case we have the following sample size n =772 from men recruits between the ages of 18 to 24

$\bar X= 69.7$ represent the sample mean for the heigth

$\sigma=2.8$ represent the population standard deviation

We want to construct a confidence interval for the true mean and we can use the following formula:

$\bar X \pm z_{\alpha/2} \frac{\sigma}{\sqrt{n}}$

The confidence level is 0.99 or 99%o then the significance level is $0.01$ and $\alpha/2 =0.005$ and if we find for a critical value in the normal tandar ddistirbution who accumulates 0.005 of the area on each tail we got:

$z_{\alpha/2}= 2.58$

And replacing we got:

$69.7 -2.58 \frac{2.8}{\sqrt{772}}=69.44$

$69.7 +2.58 \frac{2.8}{\sqrt{772}}=69.96$

And we can conclude that the true mean for the heights of mens between the ages of 18 to 24 is between 69.44 and 69.7 inches.

5 0

3 years ago

Read 2 more answers

A used-car dealer has a vehicle on the lot with a sticker price of $5999. If the

Digiron [165]

Answer:

$4999

Step-by-step explanation:

Let the cost of the car be x

<u>Then considering 20% markup, the sticker price is:</u>

x + 20% = 5999

<u>Since 20% of x is 20/100x = 0.2x,</u>

x+ 0.2x = 5999
1.2x = 5999
x = 5999/1.2
x ≈ $4999

<u>So dealer paid</u> $4999 for the car

3 0

3 years ago