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joja [24]
4 years ago
5

Is 74.3 grater than or less than 7.43

Mathematics
2 answers:
melamori03 [73]4 years ago
8 0
74.3 is greater than 7.43
iris [78.8K]4 years ago
3 0
It’s greater since it’s 74.3 compared to 7.43
74.3 is a larger number then 7.43
You might be interested in
Find the intercepts and the vertical and horizontal asymptotes, and then use them to sketch a graph of the function. f(x)=x+2/x^
hoa [83]

We have the function:

f(x)=x+\frac{2}{x^2}-16.

We must find:

0. the intercepts,

,

1. the vertical and horizontal asymptotes.

1) x-intercepts

The x-intercepts are given by the x values such that f(x) = 0. So we must find the values of x that satisfies the equation:

f(x)=x+\frac{2}{x^2}-16=0.

Solving for x, we get:

\begin{gathered} x+\frac{2}{x^2}-16=0 \\ x\cdot x^2+2-16\cdot x^2,\text{ }x\ne0, \\ x^3-16x^2+2=0. \end{gathered}

The real roots of this equation are:

\begin{gathered} x_1\approx15.9922, \\ x_2\approx0.35757, \\ x_3\approx-0.34975. \end{gathered}

So the x-intercepts are the points:

\begin{gathered} P_1=(15.9922,0), \\ P_2=(0.35757,0), \\ P_3=(-0.34975,0)\text{.} \end{gathered}

2) y-intercepts

The y-intercepts are given by the y values such that x = 0. Replacing x = 0 in the definition f(x), we see that the denominator of the second term diverges. So we conclude that there are no y-intercepts.

3) Vertical asymptotes

Vertical asymptotes are vertical lines near which the function grows without bound. From point 2, we know that the function grows without limit when x goes to zero. So one vertical asymptote is:

x=0.

4) Horizontal asymptotes

Horizontal asymptotes are horizontal lines that the graph of the function approaches when x → ±∞. We consider the limit of the function f(x) when x → ±∞:

\lim _{x\rightarrow\pm\infty}f(x)=\lim _{x\rightarrow\pm\infty}(x+\frac{2}{x^2}-16)\rightarrow\pm\infty.

We see that the function does not tend to any constant value when x → ±∞. So we conclude that there are no horizontal asymptotes.

5) Oblique asymptotes

When a linear asymptote is not parallel to the x- or y-axis, it is called an oblique asymptote or slant asymptote.

A function ƒ(x) is asymptotic to the straight line y = mx + n (m ≠ 0) if

{\displaystyle\lim _{x\to+\infty}\mleft[f(x)-(mx+n)\mright]=0\, {\mbox{ or }}\lim _{x\to-\infty}\mleft[f(x)-(mx+n)\mright]=0.}

We consider the line given by:

y=mx+n=x-16.

We compute the limit:

\begin{gathered} \lim _{x\rightarrow\pm\infty}(f(x)-(x-16)) \\ =\lim _{x\rightarrow\pm\infty}((x+\frac{2}{x^2}-16)-(x-16)) \\ =\lim _{x\rightarrow\pm\infty}(\frac{2}{x^2}) \\ =0. \end{gathered}

So we have proven that f(x) has the oblique asymptote:

y=x-16.

6) Graph

Plotting the intercepts and the asymptotes, we get the following graph:

Answer

1) x-intercepts: (-0.34975, 0), (0.35757, 0), (15.9922, 0)

2) y-intercepts: none

3) Vertical asymptotes: x = 0

4) Horizontal asymptotes: none

5) Oblique asympsotes: y = x -16

6) Graph

6 0
1 year ago
TUZ.U410)
ICE Princess25 [194]

Answer:

Part A: 15

Part B:

Point slope form: y-400=15(x-5)

Slope intercept form: y =15x+325

Standard Form: 15x-y+325=0

Part C: g(x) =15x+325

Part D: 505

Step-by-step explanation:

We are given the following

x       g(x)

5      $400

10    $475

We can see that these are two points on the line.

i.e. (5, 400) and (10, 475)

OR

x_1 = 5\\x_2 = 10\\y_1 = 400\\y_2 = 475

<u>Part A: </u>Slope of the function:

m=\dfrac{y_2-y_1}{x_2-x_1} \\\Rightarrow m = \dfrac{475-400}{10-5}\\\Rightarrow m = \dfrac{75}{5} = 15

So, slope of the line = 15

<em>It has a positive slope and the function will be increasing with the increasing value of 'x'.</em>

<em></em>

<u>Part B:</u>

Point slope form of a line is given as:

y-y_1=m(x-x_1)

Putting (x_1, y_1)\ as\ (5, 400):

y-400=15(x-5)

Slope intercept form:

y=mx+c where c is the intercept.

y =15x+c

Putting (x,y) as (5, 400) to find c:

400=15\times5+c\\\Rightarrow c = 325

So, the equation in slope intercept form:

y =15x+325

Standard form of line:

Ax+By+C=0

Rewriting the slope intercept form:

15x-y+325=0

<u>Part C:</u>

Using the function notation, putting y = g(x) in slope intercept form:

g(x) =15x+325

<u>Part D:</u>

Balance after 12 days = ?

i.e. g(x) = ? at x = 12

Putting x = 12 in g(x) =15x+325

g(12) =15\times 12+325\\\Rightarrow g(12)=505

7 0
3 years ago
I need help Nika baked three loaves of zucchini bread. Each cake needed StartFraction 17 over 4 EndFraction cups of flour. Which
statuscvo [17]

Answer:

B..

lol

Step-by-step explanation:

6 0
3 years ago
Find the sales tax for a lawnmower that cost 265.00 at a 6% tax rate?
maksim [4K]

Answer:

C. $15.90

Step-by-step explanation:

6% to a decimal is 0.06. Multiply 265.00 * 0.06 to get the answer.

3 0
3 years ago
Read 2 more answers
Consider a situation in which sampling without replacement is used to generate a random sample from each of two separate populat
Leni [432]

Answer:

Each population must be at least 10 times as large as its corresponding sample.

Step-by-step explanation:

The 10 percent rule checks that the sample is small relative to the population (that is, that the population is at least 10 times as large as the sample size) so that independence of observations within a sample is reasonable to assume.

7 0
3 years ago
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