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3 years ago

What word problem would fit for 7x+10=-3x-2

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

3 0

Answer:

A number is multiplied by 7 and the added to 10 and it is equal to when -3 is multiplied by the same number and then 2 is taken away. Find the number.

Step-by-step explanation:

interpretation: 7x+10=-3x-2

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Find each variable please!!!

elena-14-01-66 [18.8K]

Answer:

x = 6.5

Step-by-step explanation:

By property of intersecting secants outside of circle.

$6(6 + x) = 5(5 + 10) \\ 36 + 6x = 5 \times 15 \\ 6x = 75 - 36 \\ 6x = 39 \\ x = \frac{39}{6} \\ x = \frac{13}{2} \\ x = 6.5$

8 0

3 years ago

se the drawing tool to form the correct answers on the provided grid. For the sequence (1, 2, 4, 8, . . .), the index starts at

Andru [333]

Answer:

See attached

Step-by-step explanation:

For each increase of 1 in the index, the function value doubles. The size of the function value rapidly exceeds the limit of any linear grid.

We've shown a few points plotted. Perhaps it will give you the idea of what you need to do.

6 0

3 years ago

I need help please .

LuckyWell [14K]

Answer:

Step-by-step explanation:

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3 years ago

Name this polynomial by its degree: 3x² + 5x-3

Stella [2.4K]

Answer:

$\boxed{\textsf {The given polynomial is a quadratic polynomial. }}$

Step-by-step explanation:

A polynomial is given to us and we need to make the polynomial by its degree . Here the given polynomial is 3x² + 5x -3 .

$\sf\implies p(x)= 3x^2+5x-3$

So here we can see that the highest power of the variable in the given polynomial is 2 . So the polynomial is a quadratic polynomial .

★ More to Know :-

When we equate this quadratic polynomial with 0 , it becomes a quadratic equation.

That is ,

$\sf\implies p(x)= 3x^2+5x-3=0$

This is done in order to find the zeroes of the polynomial. The zeroes of the polynomial are the values for which the polynomial becomes 0 .

4 0

3 years ago

Read 2 more answers

2x^3-16x^2-40x=0 factor

ExtremeBDS [4]

The given expression is

$2x^3-16x^2-40x=0$

We extract the common factor 2x.

$\begin{gathered} 2x(x^2-8x-20)=0 \\ 2x=0\rightarrow x=0 \\ x^2-8x-20=0 \end{gathered}$

The first solution is 0.

Now, we solve the quadratic expression. We have to find two numbers whose product 20 and whose difference is 8. Those numbers are 10 and 2.

$x^2-8x-20=(x-10)(x+2)$ <h2>Hence, the given expressions expressed, as factors, is</h2> $2x^3-16x^2-40x=x(x-10)(x+2)$

3 0

1 year ago