All categories

3 years ago

I need help can you please help me please I need it

Mathematics

1 answer:

34kurt3 years ago

6 0

I’m assuming the number 5 is the speed the person is at and the equation is used to calculate the distance of the race using the time and the speed (5 mph). Please mark me brainliest It would be pretty cash money of you

You might be interested in

Somebody help me please fast

Nina [5.8K]

Answer:

768 cubic inches

Step-by-step explanation:

Volume = W x L x H = 8 x 8 x 12 = 768

8 0

3 years ago

Write the given expression as a single trigonometric function.

tatiyna

Answer:

Just did it, had a good guess.

Step-by-step explanation:

6 0

3 years ago

What is the product of 3.45 x (1.93 x 10^4)

V125BC [204]

Answer:

66,585

Step-by-step explanation:

First, solve 10^4, which is 10,000. Then, do 1.93x10,000 and get 19300. Finally, multiply 19300 by 3.45 to get 66,585.

Always use pemdas and hope this helped!

6 0

2 years ago

Please help I with give Brainiest if correct

padilas [110]

Answer:

Perimeter of the rectangle = 6 x +20

Perimeter of the rectangle = 0 x² + 6 x + 20

Step-by-step explanation:

Step(i):-

Given that the length of the rectangle = 2x +3

Given that the width of the rectangle = x +7

Perimeter of the rectangle = 2(length + width)

Step(ii):-

Perimeter of the rectangle = 2(length + width)

= 2(2 x +3 + x+7)

= 4x +6+2x+14

= 6 x +20

Final answer:-

Perimeter of the rectangle = 6 x +20

Perimeter of the rectangle = o x² + 6 x + 20

7 0

3 years ago

A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square

kondaur [170]

This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

$V = xxy = x^{2}y$

We also know that the bin is constructed from 48 square feet of sheet metal, so:

Surface area of the square base = $x^{2}$

Surface area of the rectangular sides = $4xy$

Therefore, the total area of the cube is:

$A = 48 ft^{2} = x^{2} + 4xy$

Isolating the variable y in terms of x:

$y = \frac{48- x^{2} }{4x}$

Substituting this value in V:

$V = x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}$

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

$\frac{dv}{dx} = 48-3x^{2} =0$

Solving for x:

$x = \sqrt{\frac{48}{3}} = \sqrt{16} = 4$

Solving for y:

$y = \frac{48- 4^{2} }{(4)(4)} = 2$

Then, the dimensions of the largest volume of such a bin is:

Length = 4 ft
Width = 4 ft
Height = 2 ft

And its volume is:

$V = (4^{2} )(2) = 32 ft^{3}$

8 0

3 years ago