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umka2103 [35]
3 years ago
12

Given the equation Square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.

Mathematics
2 answers:
Kisachek [45]3 years ago
6 0
Do recall that squaring and the *radical sign* cancel each other out... like so:(\sqrt{a})^{2}= a

When you put it that way, it isn't enough :P
(\sqrt{a})^{2}= a
(\sqrt{8x+1})^{2}=?

so you start with
(\sqrt{8x+1})^{2}= (5)^{2}
8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3

To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?

(extraneous solution is a invalid solution)

x=3 not extraneous


Nitella [24]3 years ago
3 0

Answer with explanation:

The given equation is

    \sqrt{8 x +1}=5\\\\ \text{Squaring both sides}}\\\\ 8x +1=25\\\\ 8 x=25-1\\\\8 x=24\\\\x=\frac{24}{8}\\\\x=3

Substituting the value of , x=3, in original equation

LHS

   \rightarrow\sqrt{8\times 3 +1}\\\\\sqrt{25}=5

=R HS,

So, x=3, is not an extraneous solution.

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the value of n is both 5times as much as the value of m and 36more than the value of m. What are the values of n and m?​
LuckyWell [14K]

Answer:

m  = 9, n = 36

Step-by-step explanation:

Here, according to the question:

(a)  value of n is  5 times as much as the value of m

⇒  <u>n =  5 x ( value of m) </u>= 5 m

or, n = 5 m

(b)  value of n is 36 more than the value of m

⇒ <u> n =  36 +  ( value of m) </u>= 36 + m

or, n = 36 +  m

Now, compering both equations, we get

5 m   =  36 +  m

or, 5  m - m = 36

⇒ 4 m = 36, or m = 36 / 4 = 9

or,m = 9

Now, for m = 9, n =  5 x m = 5 x ( 9)  = 45

Hence, m  = 9, n = 36

8 0
3 years ago
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Sorry um but help pleasee
exis [7]

Answer:

For the first one the answer is the 2nd and 3rd one

Step-by-step explanation:

the 2nd one is the 2nd and 3rd one

make brainliest please

I hope i am rigth

4 0
3 years ago
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Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 28% below the target pressure.
Inessa [10]

Answer:

Step-by-step explanation:

Hello!

The monitoring system warn the driver when the tire pressure of the vehicle is 28% below target pressure.

Be X: target tire pressure of a certain car (pounds per square inch)

a)

X= 28 psi

If the monitoring system will warn the driver when the pressure is 28% below the target pressure: X-0.28X

First step, you have to calculate the 28% of 28psi

28*0.28= 7.84

Second step, is to subtract the calculated 28% to the target pressure:

28 - 7.84= 20.16

The TPMS will trigger a warning at 20.16 psi.

b)

If X~N(μ;σ²)

μ= 28psi (since the average is on target, then the target pressure for the car will be the average value of the distribution)

σ= 3psi

P(X≤20.16)

The standard normal distribution is tabulated. Any value of any random variable X with normal distribution can be "converted" by subtracting the variable from its mean and dividing it by its standard deviation.

So to calculate each of the asked probabilities, you have to first, "transform" the value of the variable to a value of the standard normal distribution Z, then you use the standard normal tables to reach the corresponding probability.

Z= (X-μ)/σ= (20.16-28)/3= -2.61

Now you have to look for the corresponding value of probability using the Z-table. Since the value is negative you have to the use the left entry of the Z-table, in the first column you'll find the integer and first decimal of the value -2.6- and in the first row you'll find the second decimal value -.-1

The value of probability that corresponds to -2.61 is:

P(Z≤-2.61)= 0.005

c)

You have to calculate the probability of inspecting a tire at random and it being inflated within recommended range, symbolically this is:

P(30≤X≤26)= P(X≤30)-P(X≤26)

Calculate both Z values:

Z= (30-28)/3= 0.67

Z= (26-28)/3= -0.67

P(Z≤0.67)-P(Z≤-0.67)= 0.749 - 0.251= 0.498

The probability of the tire being inflated within recommended inflation range is 0.498.

I hope this helps!

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<h2>Further Explanation </h2>

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Flexible expenses are the cost that<u> typically fluctuate</u>. It can be changed, reduced, or eliminated. These include groceries and entertainment costs.  

Since flexible expenses can be changed or reduced, allocating the fixed expenses can lead to the safe side of not living beyond your means.

However, before you allocate your flexible expenses, you have to identify these costs. According to a certified financial planner (CFP) a person may need to review 6 months past their financial statements to know the average of their food-related cost if they fluctuate significantly. It is possible that some people are budgeting fixed amount for food but actually spending more after taking into account the restaurant bills or the food delivery bill for lunch and dinner. Keeping a diary of the expenses you pay with cash, such as restaurant bills and grocery purchases, can help you accurately track what you spend over a given period. Once you know your average, you can budget accordingly.

Needs vs. Wants

Flexible expenses like food and gasoline are needs. Eliminating the less important costs from your budget such as maid services can improve your cash flow.

Learn more

  1. Cash flow brainly.com/question/10714011
  2. Income brainly.com/question/9932763

Keywords: budget, expenses, flexible expenses, fixed expenses

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