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umka2103 [35]
3 years ago
12

Given the equation Square root of 8x plus 1 = 5, solve for x and identify if it is an extraneous solution.

Mathematics
2 answers:
Kisachek [45]3 years ago
6 0
Do recall that squaring and the *radical sign* cancel each other out... like so:(\sqrt{a})^{2}= a

When you put it that way, it isn't enough :P
(\sqrt{a})^{2}= a
(\sqrt{8x+1})^{2}=?

so you start with
(\sqrt{8x+1})^{2}= (5)^{2}
8x+1=25 <-- subtract 1 to both sides
8x=24 <- divide 8 to both sides
x= 3

To find out if it's an extraneous solution ask yourself: It mustn't result in a radical that I like to call... 'illegal'. Plug it into the radicand 8x+1 and make sure you get something that is not a negative number.... so, DO you get a negative number when you plug in x = 3 into the radicand?

(extraneous solution is a invalid solution)

x=3 not extraneous


Nitella [24]3 years ago
3 0

Answer with explanation:

The given equation is

    \sqrt{8 x +1}=5\\\\ \text{Squaring both sides}}\\\\ 8x +1=25\\\\ 8 x=25-1\\\\8 x=24\\\\x=\frac{24}{8}\\\\x=3

Substituting the value of , x=3, in original equation

LHS

   \rightarrow\sqrt{8\times 3 +1}\\\\\sqrt{25}=5

=R HS,

So, x=3, is not an extraneous solution.

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-1/6

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3 years ago
11. ¿Es mayor 1/4 que 0.50? Justifica tu pregunta​
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3 0
2 years ago
Eddie built the ramp shown to train his puppy to do tricks. What is the surface area of the ramp. The dimensions are 20,20,20,23
mamaluj [8]

Answer:

3775 in²

Step-by-step explanation:

The surface area of the ramp :

Area of rectangle = 20 * 23 = 460 in²

Area of rectangle = 20 * 23 = 460 in²

Area of rectangle = 25 * 23 = 575 in²

Bottom rectangle = 60 * 23 = 1380 in²

For the trapezium: (front and rear)

1/2 (base 1 + base 2) * height

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1/2(60)*15 = 450 in²

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6 0
3 years ago
How can knowing how to represent proportional relationships in different ways be useful to solving problems
Anna35 [415]

Answer:

  appropriately writing the proportion can reduce or eliminate steps required to solve it

Step-by-step explanation:

The proportion ...

  \dfrac{A}{B}=\dfrac{C}{D}

is equivalent to the equation obtained by "cross-multiplying:"

  AD = BC

This equation can be written as proportions in 3 other ways:

  \dfrac{B}{A}=\dfrac{D}{C}\qquad\dfrac{A}{C}=\dfrac{B}{D}\qquad\dfrac{C}{A}=\dfrac{D}{B}

  Effectively, the proportion can be written upside-down and sideways, as long as the corresponding parts are kept in the same order.

I find this most useful to ...

  a) put the unknown quantity in the numerator

  b) give that unknown quantity a denominator of 1, if possible.

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The usual method recommended for solving proportions is to form the cross-product, as above, then divide by the coefficient of the variable. If the variable is already in the numerator, you can simply multiply the proportion by its denominator.

<u>Example</u>:

  x/4 = 3/2

Usual method:

  2x = 4·3

  x = 12/2 = 6

Multiplying by the denominator:

  x = 4(3/2) = 12/2 = 6 . . . . . . saves the "cross product" step

__

<u>Example 2</u>:

  x/4 = 1/2 . . . . we note that "1" is "sideways" from x, so we can rewrite the proportion as ...

  x/1 = 4/2 . . . . . . written with 1 in the denominator

  x = 2 . . . . simplify

Of course, this is the same answer you would get by multiplying by the denominator, 4.

The point here is that if you have a choice when you write the initial proportion, you can make the choice to write it with x in the numerator and 1 in the denominator.

8 0
3 years ago
the diffrence of two numbers,a and b,is 21,the diffrence of five times a and two times b is 18 what are the values of a and b
Triss [41]

Answer:

a=-8

b=-29

Step-by-step explanation:

Let's assume

first number is a

second number is b

the difference of two numbers,a and b,is 21

so, we get

a-b=21

we can solve for 'a'

a=b+21

the difference of five times a and two times b is 18

so, we get

5a-2b=18

now, we can plug 'a'

5(b+21)-2b=18

now, we can solve for b

5b+105-2b=18

3b+105=18

3b=-87

b=-29

now, we can find 'a'

a=-29+21

a=-8


8 0
3 years ago
Read 2 more answers
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