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Ksju [112]
3 years ago
13

Someone help me, im not sure how to do this, so if your kind enough please help me.

Mathematics
1 answer:
vodomira [7]3 years ago
7 0
For 11. It’s yes because it’s constant and yearly and for 12. A rent is a proportional real life example because it’s constant and it doesn’t change for 9. It’s yes because it’s constant and doesn’t change for a while for 10. It’s no because it’s not a constant relationship
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The equation A = p + prt is used to find the accumulated amount, A, of an investment with principal, P, a certain interest rate,
Whitepunk [10]

Answer:

  r equals start fraction cap a minus p over p t end fraction

Step-by-step explanation:

Subtract the term non containing r, then divide by the coefficient of r.

  A=p+prt\\\\A-p=prt\\\\\dfrac{A-p}{pt}=r

4 0
3 years ago
Derek is comparing the cost of pizzas. Option A offers a large pizza at $8.00 and $0.50 per topping. Option B offers a large piz
Alisiya [41]
A...because cheese is not topping?
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4 years ago
There are 15 dogs 12 cats 3 snakes and 5 parakeets. What percent of the number of cats is the number of dogs
riadik2000 [5.3K]

\frac{12}{15}
8 0
3 years ago
HELP PLZ I'VE BEEN STUCK FOR 30 MINS<br><br>if f(x)=x/2-2 and g(x)=2x^2+x-3, find (f+g)(x)
BARSIC [14]
(f+g)(x)=f(x)+g(x)=\frac{x}{2}-2+2x^2+x-3=
2x^2+\frac{1}{2}x+\frac{2}{2}x-2-3=
2x^2+\frac{3}{2}x-5

B is answer
4 0
3 years ago
Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15. An equation of the li
pochemuha

Answer:

\displaystyle y = \frac{3}{5}\, x + (-2).

Step-by-step explanation:

The slope of a line in a plane would be m if the equation of that line could be written in the slope-intercept form y = m\, x + b for some constant b.

Find the slope of the given line by rearranging its equation into the slope-intercept form.

3\, y = (-5)\, x + 15.

\displaystyle y = \frac{(-5)}{3} \, x + 5.

Thus, the slope of the given line would be (-5) / 3.

Two lines in a plane are perpendicular to one another if and only if the product of their slopes is (-1).

Let m_{1} and m_{2} denote the slope of the given line and the slope of the line in question, respectively.

Since the two lines are perpendicular to each other, m_{1}\, m_{2} = (-1). Apply the fact that the slope of the given line is m_{1} = (-5) / 3 and solve for m_{2}, the slope of the line in question.

\begin{aligned}m_{2} &= \frac{(-1)}{m_{1}} \\ &= \frac{(-1)}{(-5) / 3} = \frac{3}{5}\end{aligned}.

In other words, the slope of the line perpendicular to 5\, x + 3\, y = 15 would be (3 / 5).

If the slope of a line in a plane is m, and that line goes through the point (x_{0},\, y_{0}), the equation of that line in point-slope form would be:

(y - y_{0}) = m\, (x - x_{0}).

Since the slope of the line in question is (3 / 5) and that line goes through the point (5,\, 1), the equation of that line in point-slope form would be:

\begin{aligned} (y - 1) = \frac{3}{5}\, (x - 5) \end{aligned}.

Rearrange this equation as the question requested:

\begin{aligned} y - 1 = \frac{3}{5}\, x - 3 \end{aligned}.

\begin{aligned} y = \frac{3}{5}\, x - 2 \end{aligned}.

\begin{aligned} y = \frac{3}{5}\, x + (-2) \end{aligned}.

7 0
2 years ago
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