The quadratic equation

can be written in the form:

Where p and q are the roots of the equation.
Given p = 4, q = -2, a = 3, the quadratic will look like this:

Finally, distribute and combine like terms to put it in standard form.
8*8*8 = 512. Te negative gets removed.
15 + 45
GCF = 15
15/15 = 1
45/15 = 3
(15 * 1) + (15 * 3) =
15(1 + 3) <===
F(x)=(2/3)x^1.5
The centroid position along the x-axis can be obtained by
integrating the function * x to get the moment about the y-axis,
then divide by the area of the graph,
all between x=0 to x=3.5m.
Expressed mathematically,
x_bar=(∫f(x)*x dx )/(∫ f(x) dx limits are between x=0 and x=3.5m
=15.278 m^3 / 6.1113 m^2
=2.500 m
The answer to 19b is 35
i’m sorry i don’t know part A