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3 years ago

one side of the right triangle is 12cm the long side of the triangle is 39 cm how long is the base of the triangle

Mathematics

1 answer:

VLD [36.1K]3 years ago

4 0

Answer: 9√17

using pythagoras theorem, we have:

the base of the triangle is $\sqrt{39^{2}-12^{2} } =9\sqrt{17}$

Step-by-step explanation:

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3 years ago

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Two quantities are related, as shown in the table:

Rashid [163]

Answer:

$y = \frac{1}{2} x + 2$ .

Step-by-step explanation:

From the given table it is clear that x and y are linearly related.

Now, any two points that satisfy the relation between x and y are sufficient to express the equation.

The first two given points are (2,3), and (4,4).

Therefore, the equation is $\frac{y - 4}{4 - 3} = \frac{x - 4}{4 - 2}$

⇒ $y - 4 = \frac{1}{2} (x - 4)$

⇒ $y - 4 = \frac{1}{2} x - 2$

⇒ $y = \frac{1}{2} x + 2$ . (Answer)

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3 years ago

The National Institute of Standards and Technology (NIST) supplies "standard materials" whose physical properties are supposed t

Lady bird [3.3K]

Answer:

$10.08-1.64\frac{0.1}{\sqrt{6}}=10.013$

$10.08+1.64\frac{0.1}{\sqrt{6}}=10.147$

So on this case the 90% confidence interval would be given by (10.013;10.147)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma =0.1$ represent the population standard deviation

n represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=10.08$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.64$