SOLUTION:
A normal distribution would model this situation because the distribution is approximately symmetrical, thus the mean, median and mode are approximately the same and the population size is large ( greater than 30).
Line 1:
Expanding the vertex form, we have
x² + 2·1.5x + 1.5² - 0.25 = x² +3x +2
Expanding the factored form, we have
x² +(1+2)x +1·2 = x² +3x +2
Comparing these to x² +3x +2, we find ...
• the three expressions are equivalent on Line 1
Line 2:
Expanding the vertex form, we have
x² +2·2.5x +2.5² +6.25 = x² +5x +12.5
Expanding the factored form, we have
x² +(2+3)x +2·3 = x² +5x +6
Comparing these to x² +5x +6, we find ...
• the three expressions are NOT equivalent on Line 2
The appropriate choice is
Line 1 only
Since the slope is -2, then m=-2. Since the y-intercept is 5, b=5. Then, we can create the equation: y=-2x+5
Since the slope is 
, then m=. Since the y-intercept is -3, b=-3.
Then, we can create the equation: y=x-3
y>3x+6
y>4/3x-5 <- (The sign is greater than or equal to btw)
