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svet-max [94.6K]
3 years ago
9

The coordinates of the vertices of △RST are R(−3, −1) , S(−1, −1) , and T(−4, −5) .

Mathematics
2 answers:
Tatiana [17]3 years ago
4 0

Given coordinates of △RST are R(−3, −1) , S(−1, −1) , and T(−4, −5) .

and coordinates of the vertices of △R′S′T′ are R′(1, −2) , S′(1, 0) , and T′(5, −3) .

Solution : We know the rule for the new coordinates of rotatation 90°counterclockwise about the origin.The rule is (h, k) ---> (-k,h).

Where (h,k) are the coordinates of original image on axes and (-k,h) are the coordinates of rotated image.

In resulting coordinates of the image first swap the x and y coordinates of the original image and then make the sign opposite of each x-coordinate.

On applying rule (h, k) ---> (-k,h), we get

R(−3, −1) --> R′(1, -3).

S(−1, −1) --> S′(1, -1).

T(−4, −5)  --> T′(5, −4).

Let us apply another rule, each of the y-coordinate is getting reduced by 1 by adding 1 to the new coordinates.

Adding 1 to y-coordinates, we get

(1, -3) --> (1,-3+1) --> R'(1,-2)

(1, -1) --> (1,-1+1) --> S'(1,0) and

(5, −4) --> (5,-4+1) --> T' (5,-3).

So, the transformations steps would be:

1) Translation 1 unit up

2) Rotation of 90 degrees counterclockwise.



DENIUS [597]3 years ago
3 0

Answer:

I think if i had the same question the answers are translation 1 unit up. and rotation of 90 degrees counterclockwise about the origin.

My answer is in the screenshot below for any future people looking for answers :-)

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To learn more about the mid-point concept, you can take a look at brainly.com/question/10956693

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