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4 years ago

How many triangles exist with the given measurements 40, 25, 115

1 answer:

3 0

We must infer that these are the angle measurements. If so, then there will be an infinite amount of solutions because we can scale a triangle with those angle measurements to a different dimension. I hope this helps! -Dan

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Linear regressions please help me i’m going to fail my class

lyudmila [28]

The equation has the form Y= a + bX,

Where:

Y is the dependent variable (that's the variable that goes on the Y axis).

X is the independent variable (i.e. it is plotted on the X axis).

b is the slope of the line.

a is the y-intercept.

3 0

3 years ago

Simplify the expression. Write the answer using scientific notation. (7 × 105)2 a. 4.9 × 1010 b. 4.9 × 1011 c. 4.9 × 109 d. 49 ×

nataly862011 [7]

Answer:

b. 4.9 × 1011

Step-by-step explanation:

Using scientific notation is similar to expressing in standard form. Given that (7 × 105)2

We open the parenthesis. This may first be expressed as

7² × 10⁽⁵⁾²

Then expand,

= 49 × 10¹⁰

To put in scientific notation, 49 = 4.9 × 10

Hence the expression becomes

= 4.9 × 10 × 10¹⁰

Using the laws of indices

= 4.9 × 10¹¹ in scientific notation

6 0

3 years ago

Find each sum 56 + (-56)

gregori [183]

Answer:

the answer is zero

56 + (-56)

8 0

3 years ago

Read 2 more answers

Emir is standing in a treehouse and looking down at a swingset in the yard next door. The angle of depression from Emir's eyelin

erma4kov [3.2K]

Answer:

15 feets

Step-by-step explanation:

From. Trigonometric relation :

Tanθ = opposite / Adjacent

Tan 33.69 = 10 / x

0.6666649 = 10 / x

x = 10 / 0.6666649

= 15 feets

Hence, base of tree to swingset is 15 feets

3 0

3 years ago

Read 2 more answers

When a scientist conducted a genetics experiments with peas, one sample of offspring consisted of 943 peas, with 717 of them hav

pshichka [43]

Using the normal approximation to the binomial distribution, it is found that:

a) 0.242 = 24.2% probability of getting 717 or more peas with red flowers.

b) Since Z < 2, 717 peas with red flowers is not significantly high.

c) Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

For each pea, there are only two possible outcomes. Either they have a red flower, or they do not. The probability of a pea having a red flower is independent of any other pea, which means that the binomial distribution is used to solve this question.

Binomial distribution:

Probability of x successes on n trials, with p probability.

Normal distribution:

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

If Z > 2, the result is considered significantly high.

If $np \geq 10$ and $n(1-p) \geq 10$ , the binomial distribution can be approximated to the normal with:

$\mu = np$

$\sigma = \sqrt{np(1-p)}$

In this problem:

943 peas, thus, $n = 943$
3/4 probability of being red, thus $p = \frac{3}{4} = 0.75$ .

Applying the approximation:

$\mu = np = 943(0.75) = 707.25$

$\sigma = \sqrt{np(1-p)} = \sqrt{943(0.75)(0.25)} = 13.297$

Item a:

Using continuity correction, this probability is $P(X \geq 717 - 0.5) = P(X \geq 716.5)$ , which is 1 subtracted by the p-value of Z when X = 716.5.

Then:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{716.5 - 707.25}{13.297}$

$Z = 0.7$

$Z = 0.7$ has a p-value of 0.758.

1 - 0.758 = 0.242

0.242 = 24.2% probability of getting 717 or more peas with red flowers.

Item b:

Since Z < 2, 717 peas with red flowers is not significantly high.

Item c:

Since 717 peas with red flowers is not a significantly high result, we cannot conclude that the scientist's assumption is wrong.

A similar problem is given at brainly.com/question/25212369

6 0

3 years ago