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goldenfox [79]
3 years ago
9

Evaluate the expression when m=6 and n=39

Mathematics
1 answer:
IRINA_888 [86]3 years ago
7 0

Answer: 639

Step-by-step explanation:

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PLEASE HELP!! WILL GIVE BRAINLIEST!!!
Murrr4er [49]

Answer:

option D

Step-by-step explanation:

Jerry solved this equation: 

3(x-\frac{1}{4})=\frac{13}{6}

In the first step , she multiplied 3 inside the parenthesis

1. 3x-\frac{3}{4}=\frac{13}{6}

In step 2, 3/4 is added on both sides

2. 3x-\frac{3}{4}+\frac{3}{4}=\frac{13}{6}+\frac{3}{4}

In step 3, we take LCD 12

3. 3x=\frac{26}{12}+\frac{9}{12}

In step 4, add the fractions

4. 3x=\frac{35}{12}

Here, 3 or 3/1 are same.

\frac{3}{1}x=\frac{35}{12}

In step 5, to remove 3/1 we multiply both sides by 1/3.

Instead of multiplying 1/3 , Jerry made an error by multiplying 3/1

\frac{1}{3} \cdot \frac{3}{1}x=\frac{1}{3} \cdot \frac{35}{12}

x=\frac{35}{36}

In step 5, he should have multiplied both sides by 1/3

7 0
3 years ago
Read 2 more answers
Finding an Equation of a Tangent Line In Exercise, find an equation of the tangent line to the graph of the function at the give
LenaWriter [7]

Answer:

Equation of tangent will be y=\frac{x}{e}

Step-by-step explanation:

We have given the function y=x^2e^{-x}

We have to find the equation of tangent at the point (1,\frac{1}{e})

Equation of tangent is equal to \frac{dy}{dx}

So \frac{dy}{dx}=x^2\frac{d}{dx}e^{-x}+e^{-x}\frac{d}{dx}2x=-x^2e^{-x}+2e^{-x}

Now we have given point (1,\frac{1}{e})

So putting these points in the equation of tangent

\frac{dy}{dx}=-1^2e^{-1}+2e^{-1}

\frac{dy}{dx}=\frac{1}{e}

Now equation of tangent passing through (1,\frac{1}{e})

y-\frac{1}{e}=\frac{1}{e}(x-1)

y=\frac{x}{e}-\frac{1}{e}+\frac{1}{e}=\frac{x}{e}

4 0
3 years ago
Not quite sure of the answer. help me out???
vodomira [7]

Answer:

C = pi * d

Step-by-step explanation:

C = 2 * pi *r

We can replace 2 * r with d since the diameter is twice the radius

C = pi * 2*r

C = pi * d

8 0
3 years ago
These roots of the polynomial equation x^4-4x^3-2x^2+12x+9=0 are 3,-1,-1. Explain why the fourth root must be a real number. Fin
Alex787 [66]

Roots with imaginary parts always occur in conjugate pairs. Three of the four roots are known and they are all real, which means the fourth root must also be real.

Because we know 3 and -1 (multiplicity 2) are both roots, the last root r is such that we can write

x^4-4x^3-2x^2+12x+9=(x-3)(x+1)^2(x-r)

There are a few ways we can go about finding r, but the easiest way would be to consider only the constant term in the expansion of the right hand side. We don't have to actually compute the expansion, because we know by properties of multiplication that the constant term will be (-3)(1)(1)(-r)=3r.

Meanwhile, on the left hand side, we see the constant term is supposed to be 9, which means we have

3r=9\implies r=3

so the missing root is 3.

Other things we could have tried that spring to mind:

- three rounds of division, dividing the quartic polynomial by (x-3), then by (x+1) twice, and noting that the remainder upon each division should be 0

- rational root theorem

4 0
3 years ago
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Use the slide splitter theorem to solve for x in the triangle below.
Yuliya22 [10]

Answer:

I THINK THE ANSWER IN X=3

Step-by-step explanation:

5 0
3 years ago
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