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3 years ago

The graph shows two lines, A and B.

Mathematics

2 answers:

EastWind [94]3 years ago

8 0

Answer:

Part A: one solution:

Part B: x = 3, y = 4.

Explanation:

1) Part A: how many solutions does the pair of equations for lines A and B have?

The solution of a system of equations in a graph is given by the intersetion of the curves that represent the equations.

In this case, there are two straight lines, which intersect in one and only one point.

Hence, the system has one solution.

2) Part B: what is the solution to the equations of lines A and B?

The solution is the pair of coordinates of the intersection point. It is (3, 4).

Therefore, the solution is x = 3, y = 4.

Ivanshal [37]3 years ago

5 0

Answer:

A) There is one solution. The answer to a system of equations is where the lines intersect. These lines only intersect once so there is one solution.

B) 3,5 is the solution because as I said the answer to a system of equations is where the lines intersect and that is where they intersect.

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The equation ý-x+4 is graphed below. Which equation would intersect this line at the point (4, 6)?

mel-nik [20]

Answer:

Your answer would be A. y=6!

Step-by-step explanation:

Have a nice day! :)

7 0

3 years ago

Alex has 70% of her weekly paycheck

drek231 [11]

Answer:

$50

Step-by-step explanation:

Weekly paycheck to be deposited = 70%

This week's deposit = $35

Therefore, we have to determine how much is Alex weekly paycheck.

To find this, we have to use unitary method.

According to the Question

Total weekly paycheck = (total deposit/ percentage to be deposited)

Therefore, Weekly paycheck = ($35/70%)

Weekly paycheck = $50.

It means Alex gets $50 per week.

4 0

3 years ago

Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

7 0

3 years ago

What is 437 divide by 60????

Korolek [52]

It would be 7.283333333

6 0

3 years ago

Read 2 more answers

1. Write a mixed number that is equivalent to 16

Bumek [7]

Answer:

15 4/4

Step-by-step explanation:

8 0

3 years ago