All categories

3 years ago

Need help ASAP !!!!!!!!!!!

Mathematics

2 answers:

Lana71 [14]3 years ago

5 0

i think the answer b or c

i hope this help

tresset_1 [31]3 years ago

5 0

Answer: Choice C

==============================

Work Shown:

m = Slope

m = (y2-y1)/(x2-x1)

m = (2-(-2))/(6-3)

m = (2+2)/(6-3)

m = 4/3

Point Slope Form

y-y1 = m(x-x1)

y-(-2) = (4/3)(x-3)

y+2 = (4/3)(x-3)

Convert to Standard Form

y+2 = (4/3)(x-3)

3(y+2) = 4(x-3)

3y+6 = 4x-12

-4x+3y = -12-6

-4x+3y = -18

You might be interested in

Vitamin D, whether ingested as a dietary supplement or produced naturally when sunlight falls on the skin, is essential for stro

tigry1 [53]

Answer:

a) The 98% confidence interval would be given (0.182;0.218).

b) We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

c) If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

d) Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

Step-by-step explanation:

Data given and notation

n=2700 represent the random sample taken

X represent the people in England who are deficient in Vitamin D

$\hat p=0.2$ estimated proportion of England people who are deficient in Vitamin D

$\alpha=0.02$ represent the significance level

Confidence =0.98 or 98%

z would represent the statistic (variable of interest)

p= population proportion of England people who are deficient in Vitamin D

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 98% confidence interval the value of $\alpha=1-0.98=0.02$ and $\alpha/2=0.01$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.33$

And replacing into the confidence interval formula we got:

$0.20 - 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.182$

$0.20 + 2.33 \sqrt{\frac{0.2(1-0.2)}{2700}}=0.218$

And the 98% confidence interval would be given (0.182;0.218).

Part b

We are 98% confident that the true proportion of of England people who are deficient in Vitamin D is between 0.182 and 0.218.

Part c

If repeated samples were taken and the 98% confidence interval computed for each sample, 98% of the intervals would contain the population proportion.

Part d

Yes since the confidence interval not contains the value 0.25, we can refute the claim at 2% of significance.

3 0

2 years ago

Can someone leave their work in the answer section or at least the solution

kenny6666 [7]

Find 6% of 3,500 and 4% of 4,000 then subtract the two

5 0

3 years ago

Need this answered ASAP

White raven [17]

Answer:

10 1/8 years?

I hope this is right!

Step-by-step explanation:

3 0

1 year ago

Read 2 more answers

The mean clotting time of blood is 7.45 seconds with a standard deviation of 3.6 seconds. what is the probability that an indiv

Usimov [2.4K]

Less than 3 is about 10.75% and greater than 13 is about 6.18%.

To find these percents, you need to find the z-score for each value. Then, use your table to find the correct percent. Be sure to find the side above 13 when you use your chart.

For less than 3:
(3 - 7.45) / 3.6 = -1.24 = The percent below this is 0.1075

For greater than 13:
(13 - 7.45) / 3.6 = 1.54 = The percent above this is 0.0618

7 0

3 years ago

Trigonometry find the missing side

Katarina [22]

Step-by-step explanation:

griminology is one of part of body

5 0

2 years ago