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3 years ago

8

How do I find the volume of a cylinder with a missing variable

1 answer:

Annette [7]3 years ago

7 0

Answer: Write the equation with the "formula" with whatever you do have.

Volume = area of base times height.

V = πr²h

Step-by-step explanation: Sometimes they just want to see what you do with the information you have. Sometimes there is a hidden clue, like a puzzle.

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Point P is the center of the circle below. What is the exact area

igor_vitrenko [27]

Answer:

$Area =192\pi$

Step-by-step explanation:

Given

$\theta = 120^o$

$r =24$

Required

The area of the shaded sector

This is calculated as:

$Area =\frac{\theta}{360} * \pi r^2$

This gives

$Area =\frac{!20}{360} * \pi *24^2$

$Area =\frac{1}{3} * \pi *576$

$Area =\pi *192$

$Area =192\pi$

6 0

2 years ago

What type of number is -100

Harlamova29_29 [7]

Answer:

The number -100 is a rational number and an integer

3 0

2 years ago

Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

NikAS [45]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ <em>factoring 96</em>

<em>since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$ </em>

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>using exponent rule - $(a^{b}) ^{c} = a^{bc}$ </em>

<em> $\sqrt{2^{5} } = 2^{5/2}$ </em>

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>doing some simple simplification and $4=2^{2}$ and 6=2*3</em>

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

<em>collecting the roots on one side and applying exponent rule</em>

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

<em>Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$ </em>

<em>7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$ </em>

<em>combining all powers of 2</em>

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

<em>Simplifying</em>

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

3 0

3 years ago

Read 2 more answers

The number of views on an interesting video after it's uploaded is represented by the following table:

defon

Answer:

The model for V(t) ,the number of views, t ,months after it's uploaded, best fits the data is $,V(t)=50(6.25)^t$

Step-by-step explanation:

Time (months) Views

0 50

2 313

4 1950

6 12,210

8 76,300

10 476,800

$(x_1,y_1)=(0,50)\\(x_2,y_2)=(2,313)\\(x_3,y_3)=(4,1950)$

$Slope = \frac{y_2-y_1}{x_2-x_1}$

$Slope = \frac{313-50}{2-0}$

Slope =131.5

$Slope = \frac{y_3-y_2}{x_3-x_2}$

$Slope = \frac{1950-313}{4-2}$

Slope =818.5

Since the slope is not same . So, it is not a linear relationship

$\frac{y_2}{y_1}=\frac{313}{50}=6.25\\\frac{y_3}{y_2}=\frac{1950}{313}=6.25$

Since the ratio between the consecutive outputs is same so, it is exponential relationship.

Formula : $y=ab^t$

Where a is the initial value = 50

b = rate of change = 6.25

The model for V(t) ,the number of views, t ,months after it's uploaded, best fits the data

So $,V(t)=50(6.25)^t$

5 0

2 years ago

How do you round to the nearest tenth?

GenaCL600 [577]

<span>Review rounding on a number line (optional). ...Write down a number with a decimal point. ...Find the tenths place. ...Look at the hundredths place. ...Round the tenths place up if the hundredths place is 5 or more. ...<span>Round down if the hundredths place is 4 or less.</span></span>

8 0

3 years ago

Read 2 more answers