1.)300.8 m to yards<br> 2.)80 yards to mm<br> 3.)15 kg/L<br> 4.)40cm/sec to mph

Over [174]

The expression is: 5x + 6y - 3

5 0

2 years ago

Alana claims that not all 4-sided polygons with 2 pairs of equal sides are parallelograms. Is she correct. Please explain why

sergiy2304 [10]

Answer:

No, she is not correct

Step-by-step explanation:

Given: Alana claims that not all 4-sided polygons with 2 pairs of equal sides are parallelograms

To check: whether she is correct or not.

Solution:

Any two-dimensional figure formed using straight lines is known as a polygon. Triangles, quadrilaterals are examples of polygons.

A parallelogram is a quadrilateral in which opposite sides are parallel.

Kite is a polygon made up of four sides with two pairs of equal sides that are adjacent to each other but it is not a parallelogram as its opposite sides are not parallel.

So, she is not correct.

6 0

2 years ago

The profit per acre from a grove of orange trees is given by x(190 − x) dollars, where x is the number of orange trees per acre.

nasty-shy [4]

Answer:

$P(x) = 190 x -x^2$

In order to maximize the last equation we can derivate the function in term of x and we got:

$\frac{dP}{dx} = 190 -2x$

And setting this derivate equal to 0 we got:

$\frac{dP}{dx} = 190 -2x=0$

And solving for x we got:

$x = 95$

And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:

$P(x=95)= 95(190-95)= 95*95 = 9025$

Step-by-step explanation:

For this case we have the following function for the profit:

$P(x) = x(190-x)$

And we can rewrite this expression like this:

$P(x) = 190 x -x^2$

In order to maximize the last equation we can derivate the function in term of x and we got:

$\frac{dP}{dx} = 190 -2x$

And setting this derivate equal to 0 we got:

$\frac{dP}{dx} = 190 -2x=0$

And solving for x we got:

$x = 95$

And for this case the value that maximize the profit would be x =95 and the corresponding profit would be:

$P(x=95)= 95(190-95)= 95*95 = 9025$

7 0

3 years ago

Read 2 more answers

Simplify x+2/x^2+2x-3 divide by x+2/x^2-x

ira [324]

$\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}$

If $x\neq-2$ , then we can immediately cancel the factors of $x+2$ :

$\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}$

Factorize the numerator and denominator:

$x^2-x=x(x-1)$

$x^2+2x-3=(x+3)(x-1)$

Next, if $x\neq1$ , then

$\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}$

8 0

3 years ago

Find the slope of the graph

olga55 [171]

3/2 since you move 3 spaces horizontally (x) and 2 spaces up (y)

3 0

2 years ago

1.)300.8 m to yards 2.)80 yards to mm 3.)15 kg/L 4.)40cm/sec to mph